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Rudik [331]
2 years ago
9

You are in downtown Chicago (where streets run N-S and E-W). You started from 600 N. Michigan Avenue, and walked 3 blocks toward

north, 4 blocks toward west, and 1 block toward north to a train station. Length of one block is 100 [m]. What is the magnitude and direction of your displacement from the start position?
Physics
1 answer:
pickupchik [31]2 years ago
4 0

Answer:

Displacement is 565.69 m at 45° west of north

Explanation:

Let north represent positive y axis and east represent positive x axis.

We have journey started from 600 N. Michigan Avenue, and walked 3 blocks toward north, 4 blocks toward west, and 1 block toward north to a train station.

3 blocks toward north = 300 j m

4 blocks toward west = -400 i m

1 blocks toward north = 100 j m

Total displacement = -400 i + 400 j m

Magnitude

     s=\sqrt{(-400)^2+400^2}=565.69m

Direction,

     \theta =tan^{-1}\left ( \frac{400}{-400}\right )=135^0

     Direction is 45° west of north.

Displacement is 565.69 m at 45° west of north

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