Answer:
2.94 x 10⁻¹⁴L
Explanation:
To solve this problem, we have to assume that the condition of this water is at standard temperature and pressure, STP.
At STP;
1 mole of gas have a volume of 22.4L
So, let us find the number of moles of this water first;
6.02 x 10²³ molecules can be found in 1 mole of a substance
7.89 x 10⁸ molecules will contain
= 1.31 x 10⁻¹⁵mole of water
So;
Volume of water = 22.4 x 1.31 x 10⁻¹⁵ = 2.94 x 10⁻¹⁴L
<span>30.973762 u ± 0.000002 u Hope this Helps >></span>
3Ba + Au3(PO)2 =Ba3(PO)2 + 3Au
<span>the loss of one or more electrons & the addition of one of more electrons</span>
262. 5cm3.
using the Boyles law formula. p1v1=p2v2
P1=760torr.
v1=525cm³
p2=760×2=1520torr.
v2=?
p1v1=p2v2
760×525=1520×v2
v2=[ 760×525]÷1520
v2= 262.5cm³
when the pressure increases, the volume decreases.