Question 3(1 point)
1 answer:
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Answer:
kp= 3.1 x 10^(-2)
Explanation:
To solve this problem we have to write down the reaction and use the ICE table for pressures:
2SO2 + O2 ⇄ 2SO3
Initial 3.4 atm 1.3 atm 0 atm
Change -2x - x + 2x
Equilibrium 3.4 - 2x 1.3 -x 0.52 atm
In order to know the x value:
2x = 0.52
x=(0.52)/2= 0.26
2SO2 + O2 ⇄ 2SO3
Equilibrium 3.4 - 0.52 1.3 - 0.26 0.52 atm
Equilibrium 2.88 atm 1.04 atm 0.52 atm
with the partial pressure in the equilibrium, we can obtain Kp.
Complete Question
The complete question is shown on the first uploaded image
Answer:
The specific heat is
Explanation:
From the question we are told that
The mass of the sample is
The mass of the water is
The initial temperature of the sample is
The initial temperature of the water is
The final temperature of the water is
Note the final temperature of water is equal to the final temperature of brass sample
The pressure is
Generally for according to the law of energy conservation
The heat lost by sample = The heat gain by water
The heat lost by brass sample is mathematically evaluated as
Where is the specific neat of the brass sample
The heat gained by water is mathematically evaluated as
where is the specific heat of water which has a constant value of
So
substituting values
