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GuDViN [60]
4 years ago
13

Suppose you put 50 ml of water in the can instead of 100 ml and heated it to 40 degrees instead of 20 degrees. in what ways if a

ny would this affect the results of the investigation
Chemistry
1 answer:
Alex4 years ago
8 0
<span>Answer: Once these values are put into the equation delta Q=mc delta T it will give you the same value for Q (change in energy) if the same fuel is used 50mL will mean it gets heated quicker making the experiment quicker 200mL would take longer to heat for the same change in temperature causing a longer experiment.</span>
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4 years ago
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sashaice [31]

Answer:

a) 90 kg

b) 68.4 kg

c) 0 kg/L

Explanation:

Mass balance:

-w=\frac{dm}{dt}

w is the mass flow

m is the mass of salt

-v*C=\frac{dm}{dt}

v is the volume flow

C is the concentration

C=\frac{m}{V+(6-3)*L/min*t}

-v*\frac{m}{V+(6-3)*L/min*t}=\frac{dm}{dt}

-3*L/min*\frac{m}{2000L+(3)*L/min*t}=\frac{dm}{dt}

-3*L/min*\frac{dt}{2000L+(3)*L/min*t}=\frac{dm}{m}

-3*L/min*\int_{0}^{t}\frac{dt}{2000L+(3)*L/min*t}=\int_{90kg}^{m}\frac{dm}{m}

-[ln(2000L+3*L/min*t)-ln(2000L)]=ln(m)-ln(90kg)

-ln[(2000L+3*L/min*t)/2000L]=ln(m/90kg)

m=90kg*[2000L/(2000L+3*L/min*t)]

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c) If time trends to infinity the  division trends to 0 and, therefore, m trends to 0. So, the concentration at infinit time is 0 kg/L.

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4 years ago
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