All categories

3 years ago

Answer ASAP!!!

Chemistry

1 answer:

eduard3 years ago

7 0

Answer:

Yes, you heard right!" she wrote for the news outlet. "Using your partner's sperm as a mask is full of a compound called spermine, which is an antioxidant which can help reduce wrinkles, smooth the skin, prevent acne or spots and give you overall healthy-looking skin.

And yes they do have st home sperm freezing kits you can order

good luck

You might be interested in

Consider the reaction 2CO(g) + O2(g)2CO2(g) Using standard thermodynamic data at 298K, calculate the entropy change for the surr

Marizza181 [45]

<u>Answer:</u> The value of $\Delta S^o$ for the surrounding when given amount of CO is reacted is 432.52 J/K

<u>Explanation:</u>

Entropy change is defined as the difference in entropy of all the product and the reactants each multiplied with their respective number of moles.

The equation used to calculate entropy change is of a reaction is:

$\Delta S^o_{rxn}=\sum [n\times \Delta S^o_{(product)}]-\sum [n\times \Delta S^o_{(reactant)}]$

For the given chemical reaction:

$2CO(g)+O_2(g)\rightarrow 2CO_2(g)$

The equation for the entropy change of the above reaction is:

$\Delta S^o_{rxn}=[(2\times \Delta S^o_{(CO_2(g))})]-[(1\times \Delta S^o_{(O_2(g))})+(2\times \Delta S^o_{(CO(g))})]$

We are given:

$\Delta S^o_{(CO_2(g))}=213.74J/K.mol\\\Delta S^o_{(O_2)}=205.14J/K.mol\\\Delta S^o_{(CO)}=197.674J/K.mol$

Putting values in above equation, we get:

$\Delta S^o_{rxn}=[(2\times (213.74))]-[(1\times (205.14))+(2\times (197.674))]\\\\\Delta S^o_{rxn}=-173.008J/K$

Entropy change of the surrounding = - (Entropy change of the system) = -(-173.008) J/K = 173.008 J/K

We are given:

Moles of CO gas reacted = 2.25 moles

By Stoichiometry of the reaction:

When 2 moles of CO is reacted, the entropy change of the surrounding will be 173.008 J/K

So, when 2.25 moles of CO is reacted, the entropy change of the surrounding will be = $\frac{173.008}{1}\times 2.25=432.52J/K$

Hence, the value of $\Delta S^o$ for the surrounding when given amount of CO is reacted is 432.52 J/K

3 0

3 years ago

galvanic cell is powered by the following redox reaction: (g) (aq) (l)(aq) (s) (aq) Answer the following questions about this ce

kotykmax [81]

Answer:

Explanation:

1. the 1/2 reaction that occurs at the cathode

3Cl2(g) +6e^- -------------> 6Cl^- (aq)

2 the 1/2 reaction that occurs at the anode

2MnO2(s) + 8OH^-(aq) ----------> 2MnO4^- (aq) + 4H2O(l) +6e^-

E0 = -0.59v

3Cl2(g) +6e^- -------------> 6Cl^- (aq)

E0 = 1.39v

3Cl2 (g) + 2MnO2 (s) + 8OH^(−) (aq)---------> 6Cl^(−) (aq) + 2MnO4^(−) (aq) + 4H2O (l)

E0cell = 0.80v

5 0

3 years ago

A gas occupies 5.31 liters at a pressure of 0.55 atm. Determine the volume at standard pressure.

yuradex [85]

Answer:

Option A; V = 2.92 L

Explanation:

If we assume a lot of things, like:

The gas is an ideal gas.

The temperature is constant.

The gas does not interchange mass with the environment.

Then we have the relation:

P*V = n*R*T = constant.

Where:

P = pressure

V = volume

n = number of moles

R = constant of the ideal gas

T = temperature.

We know that when P = 0.55 atm, the volume is 5.31 L

Then:

(0.55 atm)*(5.31 L) = constant

Now, when the gas is at standard pressure ( P = 1 atm)

We still have the relation:

P*V = constant = (0.55 atm)*(5.31 L)

(1 atm)*V = (0.55 atm)*(5.31 L)

Now we only need to solve this for V.

V = (0.55 atm/ 1 atm)*(5.31 L) = 2.92 L

V = 2.92 L

Then the correct option is A.

7 0

2 years ago

g How many turns through the citric acid cycle are required to fully oxidize all of the acetly-coA that result from 1 molecule o

faust18 [17]

Answer:

The two molecules of acetyl-CoA that are produced from a molecule of glucose goes through two turn in the citric acid cycle, one for each molecule of acetyl-CoA.

Explanation:

Glycolysis the process by which a molecule of glucose is broken down in a series of steps to yield two molecules of pyruvate. The overall equation for the reactions of glycolsis is given below:

Glucose + 2NAD+ ----> 2 Pyruvate + 2NADH + 2H⁺

Each of the two pyruvate molecules produced from glucose breakdown is further oxidized to two molecules of acetyl-CoA and CO₂ each.

2 Pyruvate ----> 2 AcetylCoA + 2CO₂

Each of the acetyl-CoA molecule then enters the citric acid cycle for its oxidation. In each turn of the cycle, one acetyl group enters as acetyl-CoA and two molecules of CO₂ leave.

7 0

3 years ago

Se construye una pila galvánica con una barra de cobre sumergida en una disolución 1M de cationes Fe+2 y una barra de plata sume

pashok25 [27]

Answer:

El potencial celular estándar, $E_{cell}$ is +0.46 V

Explanation:

Las reacciones de media célula son;

Media reacción del ánodo Cu²⁺ + 2e⁻ ↔ Cu, E ° = 0.34 V

Media reacción catódica 2Ag + 2e⁻ ⁻ 2Ag, E ° = 0.80 V

Sin embargo tenemos para hierro Fe²⁺ + 2e⁻ ↔ Fe, E ° -0.44 V

y Fe³⁺ + e⁻ ↔ Fe²⁺, E ° = 0.77 V

que es más alta que la del cobre presente, por lo tanto, el cobre se oxidará en el ánodo

Por lo tanto, en el ánodo, tendremos

Cu → Cu²⁺ + 2e⁻ (E ° = -0.34 V)

En el cátodo

2Ag + 2e⁻ → 2Ag (E ° = 0.80 V)

$E_{cell} = E_c + E_a = -0.34 + 0.8 = +0.46 \, V$

El potencial celular estándar, $E_{cell}$ = +0.46 V

4 0

3 years ago