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Andreyy89
3 years ago
13

Rank the six combinations of electric charges on the basis of the electric force acting on q1. define forces pointing to the rig

ht as positive and forces pointing to the left as negative. rank positive forces as larger than negative forces.rank the six combinations of electric charges on the basis of the electric force acting on q1. define forces pointing to the right as positive and forces pointing to the left as negative. rank positive forces as larger than negative forces.

Physics
1 answer:
wlad13 [49]3 years ago
6 0
I do not know the answer so check Google Google helps

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What is the maximum value the string tension can have before the can slips? The coefficient of static friction between the can a
Naya [18.7K]

Answer:

T= 38.38 N

Explanation:

Here

mass of can = m = 3 kg

g= 9.8 m/sec2

angle θ = 40°

From figure we see the vertical and horizontal component of tension force T

If the can is to slip - then horizontal component of tension force should become equal to force of friction.

First we find force of friction

Fs= μ R

where

μ = 0.76

R = weight of can = mg = 3 × 9.8 = 29.4 N

Now horizontal component of tension

Tx= T cos 40 = T× 0.7660  N

==>T× 0.7660 = 29.4

==> T= 38.38 N

8 0
3 years ago
In what type of circuit are all the resistances of all the circuit elements added linearly?
ycow [4]
<em>It is a series circuit.</em> 
5 0
3 years ago
Strontium has density of 2.64 g/cm3 and crystallizes with the face-centered cubic unit cell. Calculate the radius of a strontium
pantera1 [17]

Answer:

The radius of strontium atom is

2.14 E-8cm

Explanation:

Go through the attached file for a comprehensive detailed explanation.

6 0
3 years ago
What is the equivalent resistance of a circuit that contains three 10.0  resistors connected in series to a 6.0 V battery
disa [49]
The equivalent resistance of n resistors in series is given by:
R_{eq} = R_1 + R_2 + ... + R_n
In our circuit, we have three resistors of 10.0 \Omega each, therefore the equivalent resistance of the circuit is
R_{eq} = R_1 + R_2 + R_3 = 10.0 \Omega + 10.0 \Omega + 10.0 \Omega =30.0 \Omega
4 0
3 years ago
Read 2 more answers
A 2.3 kg cart is rolling across a frictionless, horizontal track toward a 1.5 kg cart that is held initially at rest. The carts
4vir4ik [10]

Answer:

Part a)

P = 7.5 kg m/s

Part b)

v = 3.26 m/s

Explanation:

As we know that two carts are moving in opposite directions

so here total momentum of two carts must be given by vector subtraction

It is given as

P = m_1\vec v_1 + m_2\vec v_2

P = (2.3)(4.5) + (1.5)(-1.9)

P = 7.5 kg m/s

Now we know that total momentum of the system is conserved here as there is no external force on this system

so the speed of the first cart when second cart was at rest is given as

P = m_1 v_1 + 0

7.5 = 2.3 v

v = 3.26 m/s

5 0
3 years ago
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