Explanation :
Edwin Hubble used a telescope to discover the movement of galaxies in 1929. He was an American Astronomer.
The telescope invented by him is called a Hubble telescope. It has a 2.4-meter mirror.
He gives the relation between the distance to a galaxy and its recessional velocity. This is known as the Hubble law. The relation is as follows :
where,
is recessional velocity.
is Hubble constant.
is distance.
<em>So, the given statement is True.</em>
Answer:
v = 87.57 m/s
Explanation:
Given,
The initial velocity of the car, u = 0
The final velocity of the car, v = 60 mi/hr
The time period of car, t = 8 s
= 0.00222 hr
The acceleration of the car is given by the formula,
a = (v -u) / t
= 60 / 0.00222
= 27027 mi/hr²
If the car has initial velocity, u = 50 mi/hr
The time period of the car, t = 5.0 s
= 0.00139 hr
Using first equations of motion
<em> v = u + at</em>
= 50 + (0.00139 x 27027)
= 87.57 mi/hr
Hence, the final velocity of the car, v = 87.57 mi/hr
I'm not positive however my guess is this.
KE=(1/2)mv^2
KE=(1/2)(55)(121)
KE=3327.5m/s^2
You might not want to use this tho.
Answer:
A variable (often denoted by x ) whose variation does not depend on that of another.
Explanation:
Answer:
minimum frequency = 170 Hz
Explanation:
given data
One path long = 20 m
second path long = 21 m
speed of sound = 340 m/s
solution
we get here destructive phase that is path difference of minimum
here λ is the wavelength of the wave
so path difference will be
21 - 20 =
λ = 2 m
and
velocity that is express as
velocity = frequency × wavelength .............1
frequency =
minimum frequency = 170 Hz