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torisob [31]
2 years ago
9

A ball is dropped from a tower that is 206 m high, How long does it take to reach the ground?

Physics
1 answer:
Slav-nsk [51]2 years ago
7 0

It will take 6.42 s for the ball that is dropped from a height of 206 m to reach the ground.

From the question given above, the following data were obtained:

Height (H) = 206 m

<h3>Time (t) =? </h3>

NOTE: Acceleration due to gravity (g) = 10 m/s²

The time taken for the ball to get to the ground can be obtained as follow:

H = ½gt²

206 = ½ × 10 × t²

206 = 5 × t²

Divide both side by 5

t^{2}  = \frac{206}{5}\\\\ t^{2} = 41.2

Take the square root of both side

t = \sqrt{41.2}

<h3>t = 6.42 s</h3>

Therefore, it will take 6.42 s for the ball to get to the ground.

Learn more: brainly.com/question/24903556

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Required Information:

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Answer:

Maximum Emf = 20.66×10⁻¹² volts

Explanation:

The maximum emf generated around the perimeter of a cell in a field is given by

Emf = BAωcos(ωt)

Where A is the area, B is the magnetic field and ω is frequency in rad/sec

For maximum emf cos(ωt) = 1

Emf = BAω

Area is given by

A = πr²

A = π(d/2)²

A = π(7.60×10⁻⁶/2)²

A = 45.36×10⁻¹² m²

We know that,

ω = 2πf

ω = 2π(72.5)

ω = 455.53 rad/sec

Finally, the emf is,

Emf = BAω

Emf = 1×10⁻³*45.36×10⁻¹²*455.53

Emf = 20.66×10⁻¹² volts

Therefore, the maximum emf generated around the perimeter of the cell is 20.66×10⁻¹² volts

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With your hand parallel to the floor and your palm upright, you lower a 3-kg book downward. If the force exerted on the book by
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According to the net force, the acceleration of the book is 16.47 m/s².

We need to know about force to solve this problem. According to second Newton's Law, the force applied to an object will be proportional to mass and acceleration. Hence, it can be written as

∑F = m . a

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From the question above, we know that

m = 3 kg

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