A ball is dropped from a tower that is 206 m high, How long does it take to reach the ground?
1 answer:
It will take 6.42 s for the ball that is dropped from a height of 206 m to reach the ground.
From the question given above, the following data were obtained:
Height (H) = 206 m
<h3>Time (t) =? </h3>NOTE: Acceleration due to gravity (g) = 10 m/s²
The time taken for the ball to get to the ground can be obtained as follow:
H = ½gt²
206 = ½ × 10 × t²
206 = 5 × t²
Divide both side by 5
Take the square root of both side
Therefore, it will take 6.42 s for the ball to get to the ground.
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Answer:
The time taken is
Explanation:
From the question we are told that
The speed of first car is
The speed of second car is
The initial distance of separation is
The distance covered by first car is mathematically represented as
Here is the initial distance which is 0 m/s
and is the final distance covered which is evaluated as
So
The distance covered by second car is mathematically represented as
Here is the initial distance which is 119 m
and is the final distance covered which is evaluated as
Given that the two car are now in the same position we have that