Calculate the normality of 1 Kg of aluminum sulfide in 5000 ml of solution.
Normality comes out to be 8.11
<h3>
Given </h3>
- Mass of solute: 1000g
- Volume of solution (V): 5000 ml = 5 liters
- Equivalent mass of solute (E) = molar mass / n-factor
n-factor for 
is 6 and molar mass is 148g
So, on calculating equivalent mass is equal to 24.66g
FORMULAE of Normality (N) = (Mass of the solute) / (Equivalent mass of the solute (E) × Volume of the solution (V)
N=
<u> N=8.11</u>
Therefore, normality of 1 kg aluminum sulfide is 8.11
Learn more about normality here brainly.com/question/25507216
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Since it talks about the number of particles, we would need the Avogadro's number which is an empirical value equal to 6.022×10²³ particles/mole. Therefore, to determine the number of particles, such as molecules, just multiple the number of moles to the Avogadro's number:
Number of Br₂ molecules = 0.42 mol *6.022×10²³ molecules/mole = 2.53×10²³ molecules
Answer:
Water
Explanation:
Hydropower plants capture the energy of falling water to generate electricity. A turbine converts the kinetic energy of falling water into mechanical energy. Then a generator converts the mechanical energy from the turbine into electrical energy.
Answer:
The correct answer is option e.
Explanation:
The lead acid battery consists lead as an anode and lead oxide as a cathode. Both the electrodes are suspended in dilute sulfuric acid which act as an electrolyte.
At anode: Oxidation
At cathode: Reduction
