Answer:
547.7 g of C₆H₁₂O₆
Solution:
The balance chemical equation is as follow,
C₆H₁₂O₆ + 6 O₂ → 6 CO₂ + 6 H₂O
According to equation,
6 moles of O₂ burns = 180.56 g of C₆H₁₂O₆
So,
18.2 moles of O₂ will burn = X g of C₆H₁₂O₆
Solving for X,
X = (18.2 mol × 180.56 g) ÷ 6 mol
X = 547.7 g of C₆H₁₂O₆
The heat (Q) required to raise the temp of a substance is:<span>Q=m∗Cp∗ΔT</span><span> where m is the mass of the object (25.0g in this case), Cp is the specific heat capacity of the substance (for water Cp = 1.00cal/gC, or 4.18J/gC,
and Dt is the change in temp.
You'll have to solve this twice, once with the Cp in calories, and once with the Cp in joules.
</span><span>1380.72 Joules</span>