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Tamiku [17]
4 years ago
14

If the direction of a magnetic field around a vertical electrical wire is counter clockwise, what direction is the electrical cu

rrent moving?
From the top of the wire to the bottom
From the bottom of the wire to the top
Counter clockwise
Clockwise
Physics
1 answer:
strojnjashka [21]4 years ago
8 0

Direction of the current:

From the bottom of the wire to the top

Explanation:

The magnetic field produced by a current-carrying wire forms concentric circles around the wire; its magnitude is given by

B=\frac{\mu_0 I}{2\pi r}

whrere

\mu_0 is the vacuum permeability

I is the current in the wire

r is the distance from the wire

The direction of the magnetic field produced by a current-carrying wire can be found by using the right-hand rule:

- The thumb of the right hand is placed in the same direction as the current

- The other fingers, wrapped around the thumb, give the direction of the magnetic field

In this case, the wire is vertical and the magnetic field is counter clockwise (looking from the top), therefore we need to put the thumb from the bottom to the top in order to get the same direction for the field: therefore, the direction of the current is

From the bottom of the wire to the top

Learn more about magnetic fields:

brainly.com/question/3874443

brainly.com/question/4240735

#LearnwithBrainly

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Explanation:

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P_1 = P_2\\V_1 I_1 = V_2 I_2

where I1 and I2 are the currents in the two coils. Re-arranging the equation, we find

\frac{I_2}{I_1}=\frac{V_1}{V_2}=\frac{15.7 V}{110 V}=0.14

which means that the current in the secondary coil is 14% of the value of the current in the primary coil.

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We can solve the problem by using the transformer equation:

\frac{N_p}{N_s}=\frac{V_p}{V_s}

where:

Np = 400 is the number of turns in the primary coil

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5 0
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solving both equation with the quadratic formula:

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