7. Mac and Tosh are arguing about the track design. Mac claims that the car is moving fastest at point F because it is furthest
1 answer:
Answer:
- Tosh is correct.
- Swap the locations of points B and F on the track and gather speed data. If Mac is correct, the speed at F (closer to the start) should be lower. (It will not be, confirming Tosh's claim.)
Explanation:
The total energy of the car is continuously being exchanged between potential energy and kinetic energy as the car moves along the track. Neglecting energy loss due to friction, the kinetic energy will be greatest when the potential energy is least, at the lowest point on the track. As a consequence we agree with Tosh that the speed will be greatest at F because it is the lowest point.
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If the track were modified to move the lowest point nearer the start, say by interchanging points B and F, then data could be gathered to show whose theory is supported. The evidence needed is the speed of the car at the new location of point F. Tosh's argument is supported if the speed at the new point F is substantially the same.
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Explanation:
The 11Ω, 22Ω, and 33Ω resistors are in parallel. That combination is in series with the 4Ω and 10Ω resistors.
The net resistance is:
R = 4Ω + 10Ω + 1/(1/11Ω + 1/22Ω + 1/33Ω)
R = 20Ω
Using Ohm's law, we can find the current going through the 4Ω and 10Ω resistors:
V = IR
120 V = I (20Ω)
I = 6 A
So the voltage drops are:
V = (4Ω) (6A) = 24 V
V = (10Ω) (6A) = 60 V
That means the voltage drop across the 11Ω, 22Ω, and 33Ω resistors is:
V = 120 V − 24 V − 60 V
V = 36 V
So the currents are:
I = 36 V / 11 Ω = 3.27 A
I = 36 V / 22 Ω = 1.64 A
I = 36 V / 33 Ω = 1.09 A
If we wanted to, we could also show this using Kirchhoff's laws.
Answer:
Explanation:
<u>The total momentum of a system is defined by:</u>
Where,
is the total momentum or it could be expressed also as
.
and
represents the masses of the objects interacting in the system.
and
are the velocities of the objects of the system.
<em>Remember: </em><em>The momentum is a fundamental physical magnitude of vector type.</em>
We have:
We are going to take the east side as positive, and the west side as negative. Then the velocity of the car B, has to be <u>negative</u>. It goes in a different direction from car A.
Then the total momentum of the system is:
To solve this problem we will use the concepts related to the electromagnetic force related to the bases founded by Coulumb, the mathematical expression is the following as a function of force per unit area:
Here,
F = Force
L = Length
k = Coulomb constant
I =Each current
d = Distance
Force of the wire one which is located along the line y to 0.47m is then we have
Considering the B is zero at
Therefore the value of y for the line in the plane of the two wires along which the total B is zero is 0.25m