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Ratling [72]
3 years ago
13

7. Mac and Tosh are arguing about the track design. Mac claims that the car is moving fastest at point F because it is furthest

along the track Tosh disagrees, claiming that the car moves fastest at point F because point F is at the lowest height Who do you agree with? Make a modification of the track design for point F and gather some evidence to support one claim or the other. Then discuss what changes you made, what observations were made, and the reasoning that supports one of the claim of either Mac or Tosh.​
Physics
1 answer:
olganol [36]3 years ago
7 0

Answer:

  • Tosh is correct.
  • Swap the locations of points B and F on the track and gather speed data. If Mac is correct, the speed at F (closer to the start) should be lower. (It will not be, confirming Tosh's claim.)

Explanation:

The total energy of the car is continuously being exchanged between potential energy and kinetic energy as the car moves along the track. Neglecting energy loss due to friction, the kinetic energy will be greatest when the potential energy is least, at the lowest point on the track. As a consequence we agree with Tosh that the speed will be greatest at F because it is the lowest point.

__

If the track were modified to move the lowest point nearer the start, say by interchanging points B and F, then data could be gathered to show whose theory is supported. The evidence needed is the speed of the car at the new location of point F. Tosh's argument is supported if the speed at the new point F is substantially the same.

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laiz [17]

The temperature of the gas is 41.3 °C.

Answer:

The temperature of the gas is 41.3 °C.

Explanation:

So on combining the Boyle's and Charles law, we get the ideal law of gas that is PV=nRT. Here P is the pressure, V is the volume, n is the number of moles, R is gas constant and T is the temperature. The SI unit of pressure is atm. So we need to convert 1 Pa to 1 atm, that is 1 Pa = 9.86923×10^{-6} atm. Thus, 171000 Pa = 1.6876 atm.

We know that the gas constant R = 0.0821 atmLMol–¹K-¹. Then the volume of the gas is given as 50 L and moles are given as 3.27 moles.

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1.6876×50=3.27×0.0821×T

Temperature = \frac{84.38}{0.268467} =314.3 K

So the temperature is obtained to be 314.3 K. As 0°C = 273 K,

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3 years ago
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finlep [7]

Answer:

Stretch can be obtained using the Elastic potential energy formula.

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Explanation:

Given:

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The formula to find EPE is given as:

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Rewriting the above expression in terms of 'x', we get:

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