BL21)

Two satellites, A and B are in different circular orbits

jek_recluse [69]

Answer:

The ratio of the orbital time periods of A and B is $\frac{1}{2}$

Solution:

As per the question:

The orbit of the two satellites is circular

Also,

Orbital speed of A is 2 times the orbital speed of B

$v_{oA} = 2v_{oB}$ (1)

Now, we know that the orbital speed of a satellite for circular orbits is given by:

$v_{o} = \farc{2\piR}{T}$

where

R = Radius of the orbit

Now,

For satellite A:

$v_{oA} = \farc{2\piR}{T_{a}}$

Using eqn (1):

$2v_{oB} = \farc{2\piR}{T_{a}}$ (2)

For satellite B:

$v_{oB} = \farc{2\piR}{T_{b}}$ (3)

Now, comparing eqn (2) and eqn (3):

$\frac{T_{a}}{T_{b}} = \farc{1}{2}$

6 0

2 years ago

What force acts on all objects, all the time on Earth?

TiliK225 [7]

The force that acts on all objects, all the time on Earth is gravitational force.

The force that surface exert on an object perpendicularly is normal reaction.

<h3>What force acts on all objects, all the time on Earth?</h3>

Force due to gravity is gravitational pull on objects due to its position on earth's surface.

The force due to gravity on object's is calculated by applying Newton's second law of motion as follows;

F = mg

where;

m is the mass of the object
g is acceleration due to gravity

The force that surface exert on an object perpendicularly is normal reaction.

Thus, the force that acts on all objects, all the time on Earth is gravitational force.

Learn more about force of gravity here: brainly.com/question/2537310

7 0

2 years ago

For a particular pipe in a pipe-organ, it has been determined that the frequencies 296 Hz and 370 Hz are two adjacent natural fr

user100 [1]

Answer:

fundamental frequency of pipe will be equal to 74 Hz

Explanation:

We have given for a particular organ pipe two adjacent frequency are 296 Hz and 370 Hz

Speed of the sound in air is 343 m/sec

We have to find the fundamental frequency for the pipe

Fundamental frequency will be equal to difference of the two adjacent frequency

So fundamental frequency = 370 - 296 = 74 Hz

So fundamental frequency of pipe will be equal to 74 Hz

8 0

3 years ago

The substances referenced in the table are being considered for use in cooking materials. Since the materials must be melted dur

frutty [35]

Brass requires more energy than silver

Aluminum requires more energy than copper

Aluminum requires more energy than brass

Explanation:

The specific heat capacity of a substance indicates the amount of heat energy required to raise 1 kg of that substance by 1 degree in temperature.

Mathematically:

$C=\frac{Q}{m\Delta T}$

where

Q is the heat supplied to the substance

m is the mass of the substance

$\Delta T$ is the change in temperature

Therefore, the higher the specific heat capacity of a substance, the more energy is needed to increase its temperature.

Here we can compare the specific heat capacity of the materials mentioned:

Silver: $C=0.233 J/gK$

Brass: $C=0.380 J/gK$

Platinum: $C=0.130 J/gK$

Aluminium: $C=0.910 J/gK$

Copper: $C=0.390 J/gK$

Therefore, the correct statements are:

Brass requires more energy than silver

Aluminum requires more energy than copper

Aluminum requires more energy than brass

Learn more about specific heat:

brainly.com/question/3032746

brainly.com/question/4759369

#LearnwithBrainly

3 0

2 years ago

A 1-kg iron frying pan is placed on a stove. The pan increases from 20°C to 250°C. If the same amount of heat is added to a pan

sergejj [24]

Here mass of the iron pan is given as 1 kg

now let say its specific heat capacity is given as "s"

also its temperature rise is given from 20 degree C to 250 degree C

so heat required to change its temperature will be given as

$Q = ms \Delta T$

$Q = 1*s*(250 - 20)$

$Q = 1*s*230$

now if we give same amount of heat to another pan of greater specific heat

so let say the specific heat of another pan is s'

now the increase in temperature of another pan will be given as

$Q = ms'\Delta T$

$1*s*230 = 1* s' * \Delta T$

now we have

$\Delta T = (\frac{s}{s'})*230$

now as we know that s' is more than s so the ratio of s and s' will be less than 1

And hence here we can say that change in temperature of second pan will be less than 230 degree C which shows that final temperature of second pan will reach to lower temperature

So correct answer is

<u>A) The second pan would reach a lower temperature.</u>

3 0

2 years ago

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