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butalik [34]
3 years ago
14

Do cars get better gas mileage with clean air filters? Gas mileage for 10 cars with dirty air filters and clean air filters was

studied. Each car was tested with a clean air filter and once with a dirty air filter (with the order of the testing randomized). What type of study is this?
Physics
1 answer:
ASHA 777 [7]3 years ago
8 0

Answer:

Explanation:

Yes.

Proper maintenance of cars or any vehicle will add more life to it and increase the quality performance.

If dirty filters of cars is changed, the gas mileage will increase resulting into a better performance of cars.

Dirty air filters reduces the capacity for it to filter the air going into engine. If air filters are not changed for a longer time it results into misfire or trouble starting.

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How does a single fixed pulley, like the one seen here, help you do work?
AlexFokin [52]
The correct answer is A.
3 0
4 years ago
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A certain refrigerator has a COP of 5.00. When the refrigerator is running, its power input is 500 W. A sample of water of mass
yulyashka [42]

Answer:

t=20s

Explanation:

To solve this problem we must apply the first law of thermodynamics, which indicates that the energy that enters a system is the same that must come out, resulting in the following equation

For this problem we will assume that the water is in a liquid state, since it is a domestic refrigerator

q=m.cp.(T2-T1)

q=heat

m=mass of water =600g=0.6Kg

cp=

specific heat of water=4186J/kgK

T2=temperature in state  2=20°C

T1=temperature in state 1=0°C

solving:

q=(0.6)(4186)(20-0)=50232J

A refrigerator is a device that allows heat to be removed to an enclosure (Qin), by means of the input of an electrical energy (W) and the heat output (Qout), the coefficient of performance COP, allows to know the ratio between the heat removed ( Qin) and the added electrical power (W), the equation for the COP is

COP=\frac{Qin}{Win}

To solve this exercise we must know the value of the heat removed to the water (Qin)

solving for Qin

Qin=(COP)(Win)

Qin=(5)(500W)=2500W

finally we remember that the definition of power is the ratio of work over time

w=work

p=power=500w

P=\frac{W}{t} \\t=\frac{W}{P} \\t=\frac{50232}{2500} \\t=20.09s

3 0
3 years ago
(c)
lys-0071 [83]
The answer is c. Twelve wants pass an obsessive frequency of the internet
7 0
4 years ago
A 120 V potential difference is applied to a space heater that dissipates 674 W during operation. (a) What is its resistance dur
Annette [7]

Answer:

(a) 21.36 ohms

(b) 5.62 A

Explanation:

Parameters given:

Potential difference, V = 120 V

Power, P = 674 W

(a) Power is given as:

P = V²/R

Where R is resistance

=> R = V²/P

R = 120²/674

R = 14400/674

R = 21.36 ohms

(b) Power is also given as:

P = I*V

Where I = Current (time rate of flow of Electric charge)

=> I = P/V

I = 674/120

I = 5.62 A

6 0
3 years ago
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Can someone who knows how to do physics please answer this
Serhud [2]

Answer:

  about 3.17647 hours

Explanation:

The appropriate relation is ...

  time = distance/speed

  time = (270 km)/(85 km/h) = 3 3/17 h ≈ 3.17647 h

It will take Derek about 3.17647 hours to drive the distance.

5 0
3 years ago
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