Where's the question?
The weight of the bicycle will be 70kg which means that the bicycle has more friction to the ground.
Option (A ) is correct.
Explanation:
susan is moving with constant velocity, so both the direction and magnitude of the velocity remains same. so the acceleration of susan =0. This is because an object gets accelerated when either the magnitude or direction of the speed changes.
now the force is given by
F= force
m= mass
a= acceleration
Here a =0
so F= 0
so the net force on susan is zero.
The tangential velocity of the car's tire is the product of the angular velocity and radius of the car's tire which is 11(r) m/s.
<h3>
Angular velocity of the tire</h3>
The angular velocity of the tire is the rate of change of angular displacement of the tire with time.
The magnitude of the angular velocity of the tire is calculated as follows;
ω = 2πN
where;
- N is the number of revolutions per second
ω = 2π x (5.25 / 3)
ω = 11 rad/s
<h3>Tangential velocity of the tire</h3>
The tangential velocity of the car's tire is the product of the angular velocity and radius of the car's tire.
The magnitude of the tangential velocity is caculated as follows;
v = ωr
where;
- r is the radius of the car's tire
v = 11r m/s
Learn more about tangential velocity here: brainly.com/question/25780931
The answer is C sorry if it’s wrong
I believe the answer would be elastic because you are pulling the sting of the bow back.
hope this helps :)
