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BARSIC [14]
3 years ago
10

Copper has a specific heat of 0.386 J/g°C. How much heat is required to increase 5.00 g of copper from 0.0°C to 10.0°C?

Physics
1 answer:
boyakko [2]3 years ago
5 0
Heat required = 0.386 * 5.00 * (10-0) = 19.3 J
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Ruby is out with her friends. Misfortune occurs and
zhannawk [14.2K]

The work done is 2.35\cdot 10^5 J

Explanation:

The work done by a force on an object is given by:

W=Fd cos \theta

where

F is the magnitude of the force

d is the displacement of the object

\theta is the angle between the direction of the force and of the displacement

In this problem, we have

F = 1080 N is the force applied on the car

d = 218 m is the displacement of the car

And assuming the force is applied parallel to the motion of the car, \theta=0^{\circ}, and so the work done is

W=(1080)(218)(cos 0^{\circ})=2.35\cdot 10^5 J

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

#LearnwithBrainly

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3 years ago
A (20*20) cm² loop has a resistance of 0.10 Ω. A magnetic field perpendicular to the loop is B = 4t - 2t², where B is in tesla a
Ilya [14]

Answer with Explanation:

We are given that

Area of loop=(20\times 20) cm^2=400\times 10^{-4} m^2

1 cm^2=10^{-4} m^2

Resistance, R=0.1\Omega

B=4t-2t^2

We know that magnetic flux

\phi=BA

Emf ,E=\mid \frac{d\phi}{dt}\mid =\mid\frac{d(BA}{dt}\mid =\mid A\frac{dB}{dt}=400\times 10^{-4}\times \frac{4t-2t^2}{dt}\mid =\mid400\times 10^{-4}\times(4-4t)\mid

Current, I=\frac{E}{R}

Current, I=\frac{\mid 400\times 10^{-4}(4-4t)\mid }{0.1}=1.6\mid (1-t)\mid

Substitute t=0 s

Then, I=1.6\mid (1-0)\mid=1.6 A

Substitute t=1 s

Then, I=1.6\mid (1-1)\mid=0

Substitute

t=2 s

Current, I=1.6\mid(1-2)\mid=1.6 A

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Ksenya-84 [330]
I'd say a weekly news magazine.
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7nadin3 [17]

Answer:

(3) Both extensional as well as compressional strain is produced

Explanation:

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2 years ago
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Sphere 1 with radius R_1 has positive charge q, Sphere 2 with radius 4.50 R_1 is far from sphere 1 and initially uncharged. The
tia_tia [17]

Answer:

Explanation:

capacitance of sphere 2 will be 4.5 times sphere 1

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V_1 / V_2 = 1

b )

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