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Marizza181 [45]
3 years ago
8

A lamp is rated for 240v,2.5A.what is the cost of using the lamp for 3hrs if 1kWh of electricity cost #12​

Physics
1 answer:
marshall27 [118]3 years ago
6 0

Answer:

≈ 22¢

Explanation:

240 / 1000 = 0.240 kV

0.240 kV(2.5 A)(3 hr) = 1.8 kW•hr

1.8 kW•hr($0.12/kW•hr) = $0.216

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Mass refers to the gravitational force on the matter in contact with the surface of a planet
Arte-miy333 [17]

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4 years ago
It costs $336.384 to run a given giant screen TV all the time for 365 days. By choosing to use your TV's power-saving feature, t
vlabodo [156]

Answer:

The amount saved in a year is $ 278.6.

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3 0
3 years ago
How to indicate kinetic energy
QveST [7]

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8 0
3 years ago
The 160-lblb crate is supported by cables ABAB, ACAC, and ADAD. Determine the tension in these wire
kakasveta [241]

Answer:

F_{AB} = 172.1356\\F_{AC} = 258.2033\\F_{AD} = 368.8004

Explanation:

Using the diagram (see attachment) we extract the following position vectors:

Vector (OA) = 6i + 0j + 0k \\Vector (OB) = 0i + 3j + 2k \\Vector (OC) = 0i - 2j + 3k

Next step is to find unit vectors u_{AB} ,u_{AC}, u_{AD}, u_{AE} as follows:

u_{AB} = \frac{vector(AB)}{magnitude(AB)} \\= \frac{OB - OA}{magnitude({vector(OB - OA))} }\\=\frac{-6i +3j+2k}{\sqrt{6^2 + 3^2+2^2} } \\\\=-0.857 i +0.429j+0.286k\\\\u_{AC} = \frac{vector(AC)}{magnitude(AC)} \\= \frac{OC - OA}{magnitude({vector(OC - OA))} }\\=\frac{-6i -2j-3k}{\sqrt{6^2 + 2^2+3^2} } \\\\=-0.857 i -0.286j+0.429k\\\\u_{AD} = +1i\\u_{AC} = -1k

Using the diagram we find the corresponding vectors Forces:

F_{AB} = F_{AB} i + F_{AB}j +F_{AB}k\\F_{AC} = F_{AC} i + F_{AC}j +F_{AC}k\\F_{AD} = F_{AD} i + F_{AD}j +F_{AD}k\\W = -160 k

Equation of Equilibrium:

Sum of forces = 0\\F_{AB}. u_{AB} + F_{AC}.u_{AC} + F_{AD}.u_{AD} + W = 0\\(-0.857F_{AB}i + 0.429F_{AB}j +0.286F_{AB}k) + (-0.857F_{AC}i - 0.286F_{AC}j +0.429F_{AC}k) + (+1F_{AD} i)  + (-160k) = 0

Comparing i , j and k components as follows:

-0.857F_{AB} -0.857F_{AC}  +1F_{AD}  = 0\\+ 0.429F_{AB} - 0.286F_{AC} = 0\\+0.286F_{AB} +0.429F_{AC}  =  160

Solving Above equation simultaneously we get:

F_{AB} = 172.1356\\F_{AC} = 258.2033\\F_{AD} = 368.8004

3 0
4 years ago
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