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Illusion [34]
3 years ago
7

What is the physics definition of work? How is work calculated? How would you calculate the amount of work done in a slapshot.

Physics
1 answer:
loris [4]3 years ago
3 0

Answer:

1) Work is a measure of energy transfer that occurs when an object is moved over a distance by an external force at least part of which is applied in the direction of the displacement. 2) Work is calculated through joules. 3) It's possible to calculate work by multiplying the amount of force applied by the distance that the force is applied. If we know the amount of force the stick applies to the puck and the distance that the stick is applying the force to the puck, we can figure out the amount of work done.

Explanation:

Hope this helped!- Nya~ :3

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How will you show that white light is made of several colours?
Leviafan [203]

Answer:

Newton passed sunlight through a glass prism to separate the colors into a rainbow spectrum. He then passed sunlight through a second glass prism and combined the two rainbows. The combination produced white light. His simple experiment proved conclusively that white light is a mixture of colors.

hope this helps

5 0
3 years ago
Orbital velocity is the average speed of a planet moving through space in its orbit around the sun. Which of the following plane
labwork [276]

The force of gravity is equal to the mass times centripetal acceleration.

Fg = m v^2 / r

The force of gravity is defined by Newton's law of universal gravitation as:

Fg = mMG / r^2

Therefore:

mMG / r^2 = m v^2 / r

MG / r = v^2

v increases as r decreases. So the planet with the smallest orbit (closest to the sun) will have the highest orbital velocity. Of the four options, that's Mercury.

4 0
3 years ago
A uniform line charge of density λ lies on the x axis between x = 0 and x = L. Its total charge is 7 nC. The electric field at x
DedPeter [7]

Answer:

The electric field at x = 3L is 166.67 N/C

Solution:

As per the question:

The uniform line charge density on the x-axis for x, 0< x< L is \lambda

Total charge, Q = 7 nC = 7\times 10^{- 9} C

At x = 2L,

Electric field, \vec{E_{2L}} = 500N/C

Coulomb constant, K = 8.99\times 10^{9} N.m^{2}/C^{2}

Now, we know that:

\vec{E} = K\frac{Q}{x^{2}}

Also the line charge density:

\lambda = \frac{Q}{L}

Thus

Q = \lambda L

Now, for small element:

d\vec{E} = K\frac{dq}{x^{2}}

d\vec{E} = K\frac{\lambda }{x^{2}}dx

Integrating both the sides from x = L to x = 2L

\int_{0}^{E}d\vec{E_{2L}} = K\lambda \int_{L}^{2L}\frac{1}{x^{2}}dx

\vec{E_{2L}} = K\lambda[\frac{- 1}{x}]_{L}^{2L}] = K\frac{Q}{L}[frac{1}{2L}]

\vec{E_{2L}} = (9\times 10^{9})\frac{7\times 10^{- 9}}{L}[frac{1}{2L}] = \frac{63}{L^{2}}

Similarly,

For the field in between the range 2L< x < 3L:

\int_{0}^{E}d\vec{E} = K\lambda \int_{2L}^{3L}\frac{1}{x^{2}}dx

\vec{E} = K\lambda[\frac{- 1}{x}]_{2L}^{3L}] = K\frac{Q}{L}[frac{1}{6L}]

\vec{E} = (9\times 10^{9})\frac{7\times 10^{- 9}}{L}[frac{1}{6L}] = \frac{63}{6L^{2}}

Now,

If at x = 2L,

\vec{E_{2L}} = 500 N/C

Then at x = 3L:

\frac{\vec{E_{2L}}}{3} = \frac{500}{3} = 166.67 N/C

4 0
4 years ago
A girl walks 5 blocks east and then two blocks north. Find her total displacement.
Vlad [161]
Her displacement would be -3 blocks

displacement = final position - initial position
4 0
3 years ago
You weigh yourself at the top of a high mountain and the scale reads 728N. If your mass is 75 kg, what is the gravitational stre
jeka94
Use. Weight = (mass)x(accel of gravity). It'll be somewhere around approx roughly about in the neighborhood of 9.706667m/sec^2 .
5 0
3 years ago
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