Question

Is a higher value for k result in a stiffer/less stretchy spring, or a less stiff/more stretchy spring?

Answer 1

Let's think about the meaning of k, the spring's constant. Hooks law states:
$F=-kx$
or, rewriting it:
$k= -\frac{F}{x}$
where F is the force applied by the spring when we compress/release it of a certain amount of displacement x.
As we can see from the formula, the higher the value of k, the stronger is the force of the spring when we compress it of a certain fixed value x, so it will be more difficult to compress it with respect to a spring with smaller k. This means that the higher k, the stiffer is the spring.

Answer 2

Answer:

if value of k is high then it results less stretchy spring

Explanation:

As we know by formula of spring force

F = kx

here we know

k = spring constant

x = stretch in the spring

Now we know that when same force is applied on two types of spring then the stretch of the spring is given as

$x = \frac{F}{k}$

so if the value of k is higher then the stretch in the spring will be less as it is inversely depends on the spring constant.

So here we can say that if value of k is high then it results less stretchy spring