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3 years ago

Buoyancy increases with the increase in the density of a) Submerged body b) Fluid

Physics

1 answer:

AlekseyPX3 years ago

4 0

Answer:

Submerged body

Explanation:

If buoyancy is greater than weight then object will float.
If buoyancy is less then weight then object will sink.
If buoyancy=weight then objects remains stable

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The amount of energy it takes to lift a box might be a function of which of the following?

Nesterboy [21]

The amount of energy it takes to lift a box might be a function of the weight of the objects inside the box. Work is proportional to force and distance. The force of the box is the weight itself of the box. Hence the answer to this problem is B.

5 0

3 years ago

A compound wall consists of parallel layers of two different materials, 10 cm of brick and 2 cm of wood. If the difference of te

RSB [31]

The temperature difference between the wooden wall is 16⁰C, and the heat current per square metre of the wall is 7,325 W/m².

<h3>Temperature difference between the wooden wall</h3>

The temperature difference between the wooden wall is calculated as follows;

Let the brick wall = wall A
Let the wooden wall = wall B
Let the area of the walls = A

$\frac{dQ_A}{dt } = \frac{dQ_B}{dt} \\\\\frac{K_A \Delta T_A \times A}{L_A} = \frac{K_B \Delta T _B \times A}{L_B}\\\\\frac{K_A \Delta T_A }{L_A} = \frac{K_B \Delta T _B}{L_B}\\\\\frac{0.5 \times 20}{0.1} = \frac{0.125 \times \Delta T _B }{0.02} \\\\100 = 6.25\Delta T _B\\\\\Delta T _B = \frac{100}{6.25} \\\\\Delta T _B = 16 \ ^oC$

<h3 /><h3>Heat flowing in the walls</h3>

Q = KL(ΔT)

Q = 0.5 x 0.1 x (20 + 273)

Q = 14.65 W

<h3>Heat current per square meter of the Walls</h3>

QA = W/A

QA = (14.65)/A

Let the area of the wall = 10 cm x 2 cm = 0.1 m x 0.02 m = 0.002 m².

QA = 14.65/0.002

QA = 7,325 W/m²

Learn more about thermal conductivity here: brainly.com/question/11213835

4 0

3 years ago

A 1-kg plastic block is neutrally buoyant when submerged in water with a density of 1 g/cm3. If the same block is placed, such t

goldenfox [79]

Answer:

-2 m/s

Explanation:

The computation of the acceleration of the block is as follows:

The volume of the block is

V = 1kg ÷ 1,000 kg/m^3 = 1 ÷ 1,000 m^3

Now at the time of submerging in the oil

Net force is

$m_g - F_B = m \times (-a)\\\\m_g - v\times S_{oil} \times g = -ma\\\\a = (\frac{v}{m} \times S_{oil} - 1) g\\\\= (\frac{1}{1000} \times 0.8 \times 1000 -1 ) \times 10\\\\$

= -2 m/s

8 0

3 years ago

Two spaceships are observed from earth to be approaching each other along a straight line. Ship A moves at 0.40c relative to the

nirvana33 [79]

Answer:

0.80 c

Explanation:

The computation of speed is shown below:-

Here, The speed of the captain ship A report for speed of the ship B which is

$S = \frac{S_A + S_B}{1 + \frac{(S_AS_B)}{c^2} }$

where

$S_A$ indicates the speed of the ship A

$S_B$ indicates the speed of the ship B

and

C indicates the velocity of life

now we will Substitute 0.40c for A and 0.60 for B in the equation which is

$S = \frac{0.40c + 0.60c}{1 + \frac{(0.40c)(0.60c)}{c^2} }$

after solving the above equation we will get

0.80 c

So, The correct answer is 0.80c

5 0

3 years ago

As you drive in your car at 22.5 mi/h, you see a child’s ball roll into the street ahead of you. You hit the brakes and stop as

evablogger [386]

Answer:

Explanation:

Speed of car =22.5miles/hr

U=22.5miles/hour

Applied brake and come to rest

Final velocity, =0

t, =2sec

Given that,

Speed=distance /time

Then,

Distance, =speed, ×time

Converting mile/hour to m/s

Given that

Use: 1 mile= 1600 m, 1 h= 3600s

22.5miles/hour × 1600m/mile × 1hour/3600s

Therefore, 22.5mile/hour=10m/s

Using speed =10m/s

Distance =speed ×time

Distance=10×2

Distance, =20m

The distance travelled before coming to rest is 20m.

5 0

3 years ago

Buoyancy increases with the increase in the density of a) Submerged body b) Fluid​

Buoyancy increases with the increase in the density of a) Submerged body b) Fluid