Which is the correct Lewis structure for carbon monoxide?
1 answer:
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Answer:
The carbocation intermediate reacts with a nucleophile to form the addition product.
Explanation:
The reaction of benzene with an electrophile is an electrophillic substitution reaction. Here the electrophile replaces hydrogen. There is no formation of carbocation as intermediate in the reaction. Infact there is transition state where the electorphile attacks on benzene ring and at the same time the hydrogen gets removed from the benzene. So a transition carbocation is formed.
The general mechanism is shown in the figure.
i) Attack of the electrophile on the benzene (which is the nucleophile)
ii) The carbocation intermediate loses a proton from the carbon bonded to the electrophile.
iii) the carbocation formation is the rate determining step.
iv) There is no formation of addition product.
Thus the wrong statement is
The carbocation intermediate reacts with a nucleophile to form the addition product.
Answer:
Ethyl propionate
Explanation:
Calculating the double bond equivalence as:
DBE = C - (H/2) - (X/2) + (N/2) +1
Where
C is the number of carbon atoms
N is the number of nitrogen atoms
X is the number of halogens
H is the number of hydrogen atoms
So, according to the formula,
DBE = 5 - (10/2) - (0/2) + (0/2) +1 = 1
It means there is one double bond or one ring.
from the NMR signal, it is clear that compound has two triplet and two quardrate group that means two -CH3 and two -CH2 groups are present.
From the splitting information, it is clear that each the -CH2- group is next to a -CH3, and vice-versa. In this case ring structure is not possible.
The chemical shift of two protons 4.13 ppm(q, 2H) is for protons next to an O atom, therefore, compound must have
.
Then the signal at 2.33 is for a -CH2-group next to a C=O. So compound must have a structure CH3-CH2-C=O. Now, there is only one way to complete the structure - by bonding the O to the C=O carbon.
So the compound is ethyl propionate
