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uranmaximum [27]
3 years ago
12

5. Which of the following can be classified as a mixture ?

Chemistry
1 answer:
podryga [215]3 years ago
5 0

5. B air is a mixture of many elements, but is not a chemically fused.


6. B Beef stew, composition varies throughout.


7. A. They can be chemically separated into their component elements, but they are all homogenous, and as such, have constant composition, which differs from the components properties, as the components must undergo a chemical change to become compounds.

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How many mol of hydrogen in 2.8 mol of caffeine.
pochemuha
Empirical formula of caffeine is C₈H₁₀N₄O₂.

In 1 mol of caffeine we have 10 mol of hydrogen.
In 2,8 mol of caffeine we have x mol of hydrogen.

x = 2,8 mol * 10 mol / 1 mol = 28 mol

ANSWER: There are 28 mol of hydrogen.

:-) ;-)
5 0
3 years ago
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Which of the following is not an example of a science? a.geology b.astrology c.astronomy d.ecology
Rasek [7]
I think it is b.astrology

6 0
3 years ago
An atom of 14 6 c carbon decays by gamma decay which atom is left after the decay
ladessa [460]
Answer is: carbon.

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7 0
3 years ago
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Calculate the percentage by mass of the indicated element in the following compounds. Hydrogen in ascorbic acid, HC6H7O6, also k
Scorpion4ik [409]

Answer: The mass percent of hydrogen in ascorbic acid is 4.5 %

Explanation:

In C_6H_8O_6, there are 6 carbon atoms, 8 hydrogen atoms and 6 oxygen atoms.

To calculate the mass percent of element in a given compound, we use the formula:

\text{Mass percent of hydrogen}=\frac{\text{Mass of hydrogen}}{\text{Molar mass of ascorbic acid}}\times 100

Mass of hydrogen = 8\times 1g/mol=8g

Molar Mass of ascorbic acid =6\times 12g/mol+8\times 1g/mol+6\times 16g/mol=176g

Putting values in above equation, we get:

\text{Mass percent of hydrogen}=\frac{8g}{176}\times 100=4.5\%

Hence, the mass percent of of hydrogen in ascorbic acid is 4.5 %.

8 0
3 years ago
The monovalent salt concentration (the predominant solute in the blood cell) for a sample of red blood cells is 0.13 moles/liter
11111nata11111 [884]

Answer:

The osmotic pressure of cell is 648.3 KPa

Explanation:

As we know the osmotic pressure is equal to

\pi = icRT

Where

i is the Van Hoff factor

c is the concentration of solution

R is the ideal gas constant

and T is the temperature.

Substituting the given values, we get -

\pi = 2 * 0.13 * 0.08206 * 300\\

\pi = 648.3 KPa

4 0
2 years ago
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