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34kurt
4 years ago
6

The equation for distance is d = st. If a car has a speed of 77.0 m/s and travels for 45.0 seconds, how far does it go?

Physics
2 answers:
BaLLatris [955]4 years ago
8 0
The equation is  d = s t , just like it says right at the beginning there.

-- Take the equation.

-- In the place where the equation says "s", erase 's' and write "(77 m/s)".

-- In the place where the equation says "t", erase 't' and write "(45 sec)".

-- NOW the equation says  d = (77 m/s) (45 sec) .

-- When there are two numbers right next to each other like that,
it means you're supposed to multiply them.

-- So multiply them.

-- Their product is equal to "d", and that's the answer. 
elena-14-01-66 [18.8K]4 years ago
3 0
Since you are given the formula all you need to do is "plug and chug"!

d = 77(45) = 3465 m = 3.465 km.
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To solve this problem it is only necessary to apply the kinematic equations of angular motion description, for this purpose we know by definition that,

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\alpha =Angular Acceleration

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For this case we have neither angular velocity nor initial angular displacement, then

\theta = \frac{1}{2}\alpha t^2

Re-arrange for \alpha,

\alpha = \frac{2\theta}{t^2}

Replacing our values,

\alpha = \frac{2(40rev*\frac{2\pi rad}{1rev})}{60^2}

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4 0
3 years ago
Two waves are superposed. one wave has an amplitude of 5 cm, and other has an amplitude of 4 cm. What is the resultant amplitude
Vsevolod [243]
If both waves have the same wavelength, then the amplitude of
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If the waves have different wavelengths, then the resultant is a beat
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4 0
3 years ago
When you must add three vectors together, what is not true this process? You must only give a magnitude of the resultant vector
vovangra [49]

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4 0
3 years ago
Steam enters a well-insulated nozzle at 200 lbf/in.2 , 500F, with a velocity of 200 ft/s and exits at 60 lbf/in.2 with a velocit
Ede4ka [16]

Answer:

386.2^{\circ}F

Explanation:

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P_1=200lbf/in^2

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v_1=200ft/s

v_2=1700ft/s

T_1=500^{\circ}F

Q=0

C_p=1BTU/lb^{\circ}F

We have to find the exit temperature.

By steady energy flow equation

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1BTU/lb=25037ft^2/s^2

Substitute the values

1\times 500+\frac{(200)^2}{25037}+0=1\times T_2+\frac{(1700)^2}{25037}

500+1.598=T_2+115.4

T_2=500+1.598-115.4

T_2=386.2^{\circ}F

7 0
4 years ago
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Answer: The coefficient of static friction is 3.85 and  The coefficient of kinetic friction is 2.8

Explanation:

in the attachment

6 0
3 years ago
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