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Marizza181 [45]
3 years ago
11

Which of the following are vectors?

Physics
1 answer:
Vitek1552 [10]3 years ago
6 0
Velocity, acceleration, force, momentum,
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A skier descends a mountain at an angle of 35.0º to the horizontal. If the mountain is 235 m long, what are the horizontal and v
Ipatiy [6.2K]
Make sure your calculator is in degrees mode

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3 years ago
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A hot-air balloon rises from ground level at a constant velocity of 3.0 m/s. One minute after liftoff, a sandbag is dropped acci
tekilochka [14]

Answer:

a) It takes 6,37 s b) The Velocity is -59,43 m/s

Explanation:

The initial variables of the balloon are:

Xo = 0 m

Vo = 3 m/s

After one minute the situation is the following:

t= 60 s

X1 = Xo + Vo*t

X1= 0 m + 3 m/s * 60s

X1= 180m

So when the bag falls, its initial variables are the following:

Xo = 180m

X1 = 0m

Vo = 3 m/s

V1= ?

a= -9,8 m/s2

The ecuation of movement for this situation is:

X = Vo*t + 1/2 a*t^{2}

So:

-180m = 3m/s*t+ 1/2*-9,8 m/s2 * t^{2}

To solve this we have

a=-9,8/2

b=3

c=180

The formula is:(-b +/- \sqrt{b^{2} -4ac}) /2a

Replacing, we get to 2 solutions, where only the positive one is valid because we are talking about time.

<u>So the answer a) is t= 6,37 s</u>

With that answer we can find the question b), with the following movement formula.

Vf = Vo + at

Vf = +3 m/s + (-) 9,8 m/s2 *6,37s

b) Vf = -59,43 m/s

5 0
3 years ago
What does the heliocentric model of the solar system state?
Anestetic [448]

b .........................

3 0
3 years ago
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Explain how newtons firdt law of motion follows the second law​
amid [387]

Answer:

Newton's second law says that F=ma, so if the force applied is zero, then the acceleration must also be zero.

Explanation:

Let's set the equation to 0 = ma. If mass is a nonzero value, then the acceleration must be zero to solve the equation. Therefore, if the force applied to an object is zero, then it will not accelerate (i.e. change speed or direction).

6 0
3 years ago
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An electron moving with a velocity v= 5.0 × 107 m/s i enters a region of space where perpendicular electric and a magnetic field
liq [111]

Answer:

The magnetic field that will allow the electron to go through the region without being deflected is 2\times 10^{-4}\ T.

Explanation:

Given that,

Velocity of the electron, v=5\times 10^7\ m/s

Electric field, E=10^4\ V/m\ j

We need to find the magnetic field that will allow the electron to go through the region without being deflected. It can be calculated as :

qE=qvB\ \sin\theta

Here, \sin\theta=90^{\circ}

E=vB\\\\B=\dfrac{E}{v}\\\\B=\dfrac{10^4}{5\times 10^7}\\\\B=2\times 10^{-4}\ T

So, the magnetic field that will allow the electron to go through the region without being deflected is 2\times 10^{-4}\ T.

6 0
3 years ago
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