Answer:
2.4 moles of oxygen are needed to react with 87 g of aluminium.
Explanation:
Chemical equation:
4Al(s) + 3O₂(l) → 2AlO₃(s)
Given data:
Mass of aluminium = 87 g
Moles of oxygen needed = ?
Solution:
Moles of aluminium:
Number of moles of aluminium= Mass/ molar mass
Number of moles of aluminium= 87 g/ 27 g/mol
Number of moles of aluminium= 3.2 mol
Now we will compare the moles of aluminium with oxygen.
Al : O₂
4 : 3
3.2 : 3/4×3.2 = 2.4 mol
2.4 moles of oxygen are needed to react with 87 g of aluminium.
Explanation:
13 are the number of atoms
Answer:
How may we help kind sir
Explanation:
and if this was for points thanks
The balanced chemical equation for the standard formation reaction of liquid acetic acid is given as ,
→ 
The reaction that form the products from their elements in their standard state is called formation of reaction .The acetic acid consist C , H , and O , So, determine their standard state . Carbon is graphite at 25°C and 1 atm , whereas hydrogen and oxygen are diatomic gases . Hence , we start with unbalanced reaction.
→ 
The balanced chemical equation for the standard formation reaction of liquid acetic acid as,
→ 
The combustion of liquid acetic acid is given as,
→
ΔH =-873
learn more about balancing chemical equation
brainly.com/question/15052184
#SPJ4