Answer:
option D is correct
Explanation:
no of moles in 3 grams of HCL=3/36=0.08
if 1 mole of HCL require 1 mole of NaOH then 0.08 moles required 0.08 moles of NaOH
mass of 0.08 moles of NaOH=moles*molar mass=0.08*40=3.2 grams
so 3 grams are required in the reaction
THe balanced chemical reaction would be:
Na2CO3 + H2SO4 = Na2SO4 + H2O + CO2
We first convert the mass of sulfuric acid solution to moles by the molar mass. Then, we relate H2SO4 with Na2CO3 from the reaction. We do as follows:
<span>6.05×10^3 kg H2SO4 ( 1 kmol / 98.08 kg) ( 1 kmol Na2CO3 / 1 kmol H2SO4 ) ( 105.99 kg / kmol ) = 6537.92 kg Na2CO3 needed</span>
Exothermic reactions:
1) release heat to the surroundings
2) the change of enthalpy, ΔH, is negative: ΔH < 0
3) the temperature of the system increases
With that you can conclude about every equation given:
<span>NH3(g) + 12.0 kcal → ½N2(g) + 3/2 H2(g) : is not exothermic because heat in the side of the reactants means that heat is being used, not released.
C(graphite) → C(diamond), ΔH = - 0.45 kcal : is exothermic because ΔH is negative
C + 2S → CS2, ΔH = 27,550 cal: is not exothermic because ΔH is positive
CH4 + 2O2 → CO2 + 2H2O + 212,800 cal : is exothermic because heat appears as a product of the reaction, which means that it is released.
2H2O → 2H2 + O2, ΔH = +58 kcal : is not exothermic because ΔH is positive.</span>
<span>There is an organic molecule. This means that it is made up of carbon and hydrogen atoms and forms the building blocks of the molecules within living creatures and organisms. This molecule is a hydrocarbon and is made completely out of carbon and hydrogen atoms.</span>
the first law says that the change in internal energy of a system is given by:
δ<span>E = δq + δw</span>
where δ<span>E is the i change in internal energy, </span>
<span>δq is the amount of thermal energy added to the system from the surroundings </span>
<span>δw is the l work done *on* the system *by* the surroundings. </span>
<span>For a system only undergoing expansion work,
δw = -p</span>δ<span>V, so: </span>
δE = δq - p δ<span>V </span>
when δV = 0, then δe=δq
