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Anit [1.1K]
4 years ago
14

Dalton’s atomic theory included which idea?

Chemistry
1 answer:
Kazeer [188]4 years ago
6 0

Answer:

Everything is composed of atoms, that are the indivisible building blocks of matter that cannot be destroyed. All atoms of an element are identical.

Explanation:

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iris [78.8K]

Answer:

3 because it the element that combined the form

7 0
2 years ago
What occurs along a convergent plate boundary ?
Margaret [11]

Answer:

Two plates pull towards each other

Explanation:

Along a convergent plate boundary, two plates moves towards each other as the move in the same direction.

This results in different forms of plate interactions depending on the plate types.

  • At an ocean - ocean and continental - ocean convergent front, subduction of the oceanic plate occurs. This is because the oceanic plate below is denser than the asthenosphere.
  • At a continental - continental convergent front, the continental crust is pulls upward and build up as a mountain.
  • The subduction produces trenches and some volcanic islands.
3 0
3 years ago
Read 2 more answers
Elements in the 2nd family/group gain or lose electrons? *
Savatey [412]
They lose electrons
6 0
3 years ago
How to know if something is actually white gold?
Alla [95]
White gold is made out of yellow gold mixed with other metals, which are added to make the alloy harder and whiter.
Even when mixed with whiter metals, white gold still retains a yellowish hue.

The quality characteristic most often used to evaluate white gold is its karat.
4 0
3 years ago
How many particles are in 47.7 g of Magnesium? (Round the average
Lynna [10]

Answer:

1.18 × 10²⁴ particles Mg

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

<u>Step 1: Define</u>

47.7 g Mg

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of Mg - 24.31 g/mol

<u>Step 3: Convert</u>

<u />47.7 \ g \ Mg(\frac{1 \ mol \ Mg}{24.31 \ g \ Mg} )(\frac{6.022 \cdot 10^{23} \ particles \ Mg}{1 \ mol \ Mg} ) = 1.18161 × 10²⁴ particles Mg

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

1.18161 × 10²⁴ particles Mg ≈ 1.18 × 10²⁴ particles Mg

3 0
3 years ago
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