The 4C matrix is obtained when all elements of matrix C are multiplied by 4. It <span>has all the same elements as C, only multiplied by 4.
Let's analyze all matrices
A. Not all elements of A can be divided by 4 (3 can not be divided by 4, the solution is not a whole number).
B. All elements of matrix B can be divided by 4, which means that B is a $C matrix (there is a matrix C which multiplied by 4 gives the matrix B).
C. Not all elements of C can be divided by 4.
D. Not all elements of D can be divided by 4.
Solution: B
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Answer:
3
Step-by-step explanation:
Answer:
tgh
Step-by-step explanation:
The correct question is
Part A: Explain why the x-coordinates of the points where the graphs of the equations y = 4−x and y = 8-x^-1 intersect are the solutions of the equation 4−x = 8-x^-1<span>.
Part B: Make tables to find the solution to 4−x = </span>8-x^-1<span>. Take the integer values of x between −3 and 3.
Part C: How can you solve the equation 4−x = </span>8-x^-1 graphically?
Part A. We have two equations: y = 4-x and y = 8-x^-1
Given two simultaneous equations that are both to be true, then the solution is the points where the lines cross. The intersection is where the two equations are equal. Therefore the solution that works for both equations is when
4-x = 8-x^-1
This is where the two graphs will cross and that is the common point that satisfies both equations.
Part B
see the attached table
the table shows that one of the solutions is in the interval [-1,1]
Part C To solve graphically the equation 4-x = 8-x^-1
We would graph both equations: y = 4-x and y = 8-x^-1
The point on the graph where the lines cross is the solution to the system of equations.
using a graph tool
see the attached figure N 2
the solutions are the points
(-4.24,8.24)
(0.24,3.76)
Answer:
Not sure but 2 would be the same as 1 so 39.5 and 3 and 4 would be 50.5
Step-by-step explanation:
1 and 3 make a right angle and so does 4 and 2 so all I did was subtract 39.5 from 90 since a right angle=90 degrees