I think it may be c, 1.7 v. I work with electricity a lot.
Answer:
2917.4 m/s
Explanation:
From the question given above, the following data were:
Gravitational acceleration of the Moon (g) = 0.25 times the gravitational acceleration of the earth
Radius (r) of the Moon = 1737 Km
Escape velocity (v) =?
Next, we shall determine the gravitational acceleration of the Moon. This can be obtained as follow:
Gravitational acceleration of the earth = 9.8 m/s²
Gravitational acceleration of the Moon (g) = 0.25 times the gravitational acceleration of the earth
= 0.25 × 9.8 = 2.45 m/s²
Next, we shall convert 1737 Km to metres (m). This can be obtained as follow:
1 Km = 1000 m
Therefore,
1737 Km = 1737 Km × 1000 m / 1 Km
1737 Km = 1737000 m
Thus, 1737 Km is equivalent to 1737000 m
Finally, we shall determine the escape velocity of the rocket as shown below:
Gravitational acceleration of the Moon (g) = 2.45 m/s²
Radius (r) of the moon = 1737000 m
Escape velocity (v) =?
v = √2gr
v = √(2 × 2.45 × 1737000)
v = √8511300
v = 2917.4 m/s
Thus, the escape velocity is 2917.4 m/s
Answer:
A
Explanation:
warm air rises creating low presure
cold air sinks creating high presure
so this means that temprature is realated to presure.
Answer:
a) 
b) 
c) 
Explanation:
From the question we are told that:
Initial angular velocity 
Initial Length 
Final angular velocity 
Final Length 
a)
Generally the rotation with the greater speed is

b)
Generally the equation for centripetal acceleration at 8.16 is mathematically given by



c)
At 6.35 rev/s


They have a direct relationship. As mass increases, kinetic energy increases.