Answer:
V = 0.39 m/s
Explanation:
Given that,
Mass of hockey puck, m = 0.2 kg
Mass of goalie = 40 kg
Speed of hockey puck, v = 80 m/s
We need to find the speed with which the goalie slide on the slide. Let V be the speed. Using the conservation of momentum as follows :
So, the required speed is 0.39 m/s.
Answer:
Explanation:
A pressure that causes the Hg column to rise 1 millimeter is called a torr. The term 1 mmHg used can replaced by the torr.
1 atm = 760 torr = 14.7 psi.
A.
120 mmHg
Psi:
760 mmHg = 14.7 psi
120 mmHg = 14.7/760 * 120
= 2.32 psi
Pa:
1mmHg = 133.322 Pa
120 mmHg = 120 * 133.322
= 15998.4 Pa
B.
80 mmHg
Psi:
760 mmHg = 14.7 psi
80 mmHg = 14.7/760 * 80
= 1.55 psi
Pa:
1mmHg = 133.322 Pa
80 mmHg = 80 * 133.322
= 10665.6 Pa
Explanation:
the answer is y=strong winds move sand dunes in the desert
Answer:
F = 2,894 N
Explanation:
For this exercise let's use Newton's second law
F = m a
The acceleration is centripetal
a = v² / r
Angular and linear variables are related.
v = w r
Let's replace
F = m w² r
The radius r and the length of the rope is related
cos is = r / L
r = L cos tea
Let's replace
F = m w² L cos θ
Let's reduce the magnitudes to the SI system
m = 101.7 g (1 kg / 1000g) = 0.1017 kg
θ = 5 rev (2π rad / rev) = 31,416 rad
w = θ / t
w = 31.416 / 5.1
w = 6.16 rad / s
F = 0.1017 6.16² 0.75 cos θ
F = 2,894 cos θ
The maximum value of F is for θ equal to zero
F = 2,894 N
