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klasskru [66]
3 years ago
13

Rx + sx/t = 1 solve for x

Mathematics
2 answers:
MAXImum [283]3 years ago
4 0
(rx + sx) / t = 1....multiply both sides by t
rx + sx = t...factor the left side
x(r + s) = t ...divide both sides by (r + s)
x = t / (r + s) <===

abx - cdx = 15m...factor left side
x(ab - cd) = 15m...divide both sides by (ab - cd)
x = (15m) / (ab - cd) <====

Lubov Fominskaja [6]3 years ago
3 0
Thanks for your question!

First thing we have to do here is take t to the other side by multiplication:

rx + sx = t

Now, group together, x as the GCF:

x(r+s) = t

Now, divide

x = t/(r+s)

Hope this helps!
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3x+2(5x-3)=7 multi step equation
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3x+2(5x-3)=7

3x+10x-6=7

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Mr. McKay wrote an algebra test with a total of 15 questions consisting of multiple choice and short response style questions. M
tankabanditka [31]

Step-by-step explanation:

x = number of multiple choice questions

y = number of short response questions

x + y = 15

5x + 10y = 100

=>

x + 2y = 20

let's subtract the first from the second equation :

x + 2y = 20

- x + y = 15

--------------------

0 y = 5

x + y = 15

x + 5 = 15

x = 10

to graph you need to consider both equations as linear functions. and you need to transform them into e.g. a slope intercept form : y = ax + b

a is the slope, b is the y- intercept.

x + y = 15

transforms to

y = -x + 15

this line goes e.g. through the points (0, 15) and (1, 14).

and

x + 2y = 20

transforms to

2y = -x + 20

y = -x/2 + 10

this line goes e.g through (0, 10) and (2, 9).

the crossing point of both lines is the solution and should therefore be the point (10, 5) as calculated above.

5 0
2 years ago
The formula for the resistance, R, of a conductor with voltage, V, and current , I , is R= V/I. Solve for V.
borishaifa [10]

Answer:

T+V/I

Step-by-step explanation:

multiply both sides by I to get rid of fractions ti=V

7 0
3 years ago
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4. Sam Howard's bank charges a $1.23
Mamont248 [21]
The answer is D I know that because I do this all the time
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3 years ago
The probability that a grader will make a marking error on any particular question of a multiple-choice exam is 0.15. If there a
sashaice [31]

Answer:

P(X=0)=(10C10)(0.15)^{0} (1-0.15)^{10-0}=0.1969

P(X \geq 1)= 1-P(X

P(X=0)=(nCn)(p)^{0} (1-p)^{n-0}=(1-p)^n

P(X \geq 1)= 1-P(X

Step-by-step explanation:

Previous concepts

A Bernoulli trial is "a random experiment with exactly two possible outcomes, "success" and "failure", in which the probability of success is the same every time the experiment is conducted". And this experiment is a particular case of the binomial experiment.

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

The complement rule is a theorem that provides a connection between the probability of an event and the probability of the complement of the event. Lat A the event of interest and A' the complement. The rule is defined by: P(A)+P(A') =1

Solution to the problem

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=10, p=0.15)

what is the probability that no errors are made?

For this case means that all the questions were correct so we want this probability:

P(X=0)=(10C10)(0.15)^{0} (1-0.15)^{10-0}=0.1969

what is the probability that at least one error made?

For this case we want this probability:

P(X \geq 1)

And we can use the complement rule:

P(X \geq 1)= 1-P(X

If there are n questions and the probability of a marking error is p rather than 0.15, give expressions for the probabilities of no errors  and at least one error

P(X=0)=(nCn)(p)^{0} (1-p)^{n-0}=(1-p)^n

P(X \geq 1)= 1-P(X

8 0
3 years ago
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