Answer:
••• like a story pole but has information for only one portion of the wall. system. methods and materials of construction.
Da, sigur. cu ce ai nevoie de ajutor?
Answer:
Power required to overcome aerodynamic drag is 50.971 KW
Explanation:
For explanation see the picture attached
Answer:
The tube surface temperature immediately after installation is 120.4°C and after prolonged service is 110.8°C
Explanation:
The properties of water at 100°C and 1 atm are:
pL = 957.9 kg/m³
pV = 0.596 kg/m³
ΔHL = 2257 kJ/kg
CpL = 4.217 kJ/kg K
uL = 279x10⁻⁶Ns/m²
KL = 0.68 W/m K
σ = 58.9x10³N/m
When the water boils on the surface its heat flux is:
![q=0.149h_{fg} \rho _{v} (\frac{\sigma (\rho _{L}-\rho _{v})}{\rho _{v}^{2} } )^{1/4} =0.149*2257*0.596*(\frac{58.9x10^{-3}*(957.9-0.596) }{0.596^{2} } )^{1/4} =18703.42W/m^{2}](https://tex.z-dn.net/?f=q%3D0.149h_%7Bfg%7D%20%5Crho%20_%7Bv%7D%20%28%5Cfrac%7B%5Csigma%20%28%5Crho%20_%7BL%7D-%5Crho%20_%7Bv%7D%29%7D%7B%5Crho%20_%7Bv%7D%5E%7B2%7D%20%7D%20%20%29%5E%7B1%2F4%7D%20%3D0.149%2A2257%2A0.596%2A%28%5Cfrac%7B58.9x10%5E%7B-3%7D%2A%28957.9-0.596%29%20%7D%7B0.596%5E%7B2%7D%20%7D%20%29%5E%7B1%2F4%7D%20%3D18703.42W%2Fm%5E%7B2%7D)
For copper-water, the properties are:
Cfg = 0.0128
The heat flux is:
qn = 0.9 * 18703.42 = 16833.078 W/m²
![q_{n} =uK(\frac{g(\rho_{L}-\rho _{v}) }{\sigma })^{1/2} (\frac{c_{pL}*deltaT }{c_{fg}h_{fg}Pr } \\16833.078=279x10^{-6} *2257x10^{3} (\frac{9.8*(957.9-0.596)}{0.596} )^{1/2} *(\frac{4.127x10^{3}*delta-T }{0.0128*2257x10^{3}*1.76 } )^{3} \\delta-T=20.4](https://tex.z-dn.net/?f=q_%7Bn%7D%20%3DuK%28%5Cfrac%7Bg%28%5Crho_%7BL%7D-%5Crho%20_%7Bv%7D%29%20%20%20%20%20%7D%7B%5Csigma%20%7D%29%5E%7B1%2F2%7D%20%28%5Cfrac%7Bc_%7BpL%7D%2AdeltaT%20%7D%7Bc_%7Bfg%7Dh_%7Bfg%7DPr%20%20%7D%20%5C%5C16833.078%3D279x10%5E%7B-6%7D%20%2A2257x10%5E%7B3%7D%20%28%5Cfrac%7B9.8%2A%28957.9-0.596%29%7D%7B0.596%7D%20%29%5E%7B1%2F2%7D%20%2A%28%5Cfrac%7B4.127x10%5E%7B3%7D%2Adelta-T%20%7D%7B0.0128%2A2257x10%5E%7B3%7D%2A1.76%20%7D%20%29%5E%7B3%7D%20%5C%5Cdelta-T%3D20.4)
The tube surface temperature immediately after installation is:
Tinst = 100 + 20.4 = 120.4°C
For rough surfaces, Cfg = 0.0068. Using the same equation:
ΔT = 10.8°C
The tube surface temperature after prolonged service is:
Tprolo = 100 + 10.8 = 110.8°C
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