1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
JulijaS [17]
3 years ago
13

The minimum safe working distance from exposed electrical conductors

Engineering
1 answer:
SVEN [57.7K]3 years ago
4 0

Answer:

b

Explanation:

You might be interested in
An aluminum cylinder bar ( 70 GPa E m = ) is instrumented with strain gauges and is subject to a tensile force of 5 kN. The diam
Stells [14]

Find the complete solution in the given attachments.

Note: The complete Question is attached in the first attachment as the provided question was incomplete

7 0
4 years ago
A 4 cm diameter sphere of copper is initially at a temperature of 95 °C. It is placed in a very large water bath at time t- 0. T
avanturin [10]

Answer:112.376 s

Explanation:

Given

T_i=95^{\circ}C

T_f=35^{\circ}C

T_\infty \left ( ambient\right )=25^{\circ}C

h=400 watts/\left ( m^{2}^{\circ}C\right )

c=0.385 J/\left ( m^2^{\circ}C\right )

\rho =9 gm/cm^{3}

Using Newton's law of cooling

\frac{T_i-T_{\infty}}{T-T_{\infty}}=e^{\frac{ht}{\rho L_{c}c}}

\frac{95-25}{35-25}=e^{\frac{400\times 3\times 10^{-4}\times t}{9\times 2\times 0.385}}

7=e^{1.7316\times 10^{-2}\times t}

Taking log both side

t=112.376sec

4 0
3 years ago
Who wants me to make a device to resurrect Juice Wrld
Aleksandr-060686 [28]
Lolololollolollolollolololo
5 0
3 years ago
A glass plate is subjected to a tensile stress of 40 MPa. If the specific surface energy is 0.3 J/m2 and the modulus of elastici
Pavlova-9 [17]

Answer:

8.24μm

Explanation:

The theory of brittle fracture was used to solve this problem.

And if you follow through with the attachment made a the subject of the formula

Such that,

a = 2x(69x10⁹)x0.3/pi(40x10⁶)²

= 4.14x10¹⁰/5.024x10¹⁵

= 8.24x10^-06

= 8.24μm

This is the the maximum length of the surface flaw

4 0
3 years ago
A specimen of copper having a rectangular cross section 15.2 mm × 19.1 mm (0.60 in. × 0.75 in.) is pulled in tension with 44,500
lukranit [14]

Answer:

The resulting strain is 1.39\times 10^{-3}.

Explanation:

A specimen of copper having a rectangular cross section 15.2 mm × 19.1 mm

Force, F = 44,500 N

Th elastic modulus of Cu to be 110 GPa

The resulting strain is given by the formula as follows :

\epsilon=\dfrac{F}{AE}

E is elastic modulus of Cu is are of cross section

\epsilon=\dfrac{44500}{15.2\times 19.1\times 10^{-6}\times 110\times 10^9}\\\\\epsilon=1.39\times 10^{-3}

So, the resulting strain is 1.39\times 10^{-3}.

6 0
4 years ago
Other questions:
  • If you're carrying a load that extends beyond the sides of your vehicle, you don't need to clearly mark it unless it extends mor
    13·2 answers
  • Water is being heated in a closed pan on top of a range whilebeing stirred by a paddle wheel. During the process 30kJ of heat is
    11·1 answer
  • The Canadair CL-215T amphibious aircraft is specially designed to fight fires. It is the only production aircraft that can scoop
    7·1 answer
  • Plant scientists would not do which of the following?
    7·2 answers
  • If the channel-Length modulation effect is neglected, ID in the saturation region is considered to be independent of VDS
    14·1 answer
  • Identify the part of the direct current motor​
    9·1 answer
  • An electron is traveling with initial kinetic energy K in a uniform electric field. The electron comes to rest momentarily after
    12·1 answer
  • When an object is plumb, it is _____.
    11·2 answers
  • Question in Probability and Statistics 2<br>​
    10·1 answer
  • As you have learned, not all motor oils are the same. What are two things that make them different?.
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!