The minimum safe working distance from exposed electrical conductors

A work element in a manual assembly task consists of the following MTM-1 elements: (1) R16C, (2) G4A, (3) M10B5, (4) RL1, (5) R1

ella [17]

Answer:

a)

1) R16C ; Tn = 17 TMU

2) G4A ; Tn = 7.3 TMU

3) M10B5 ; Tn = 15.1 TMU

4) RL1 ; Tn = 2 TMU

5) R14B ; Tn = 14.4 TMU

6) G1B ; Tn = 3.5 TMU

7) M8C3 ; Tn = 14.7 TMU

8) P1NSE ; Tn = 10.4 TMU

9) RL1 ; Tn = 2 TMU

b) 3.1 secs

Explanation:

a) Determine the normal times in TMUs for these motion elements

1) R16C ; Tn = 17 TMU

2) G4A ; Tn = 7.3 TMU

3) M10B5 ; Tn = 15.1 TMU

4) RL1 ; Tn = 2 TMU

5) R14B ; Tn = 14.4 TMU

6) G1B ; Tn = 3.5 TMU

7) M8C3 ; Tn = 14.7 TMU

8) P1NSE ; Tn = 10.4 TMU

9) RL1 ; Tn = 2 TMU

b ) Determine the total time for this work element in seconds

first we have to determine the total TMU = ∑ TMU = 86.4 TMU

note ; 1 TMU = 0.036 seconds

hence the total time for the work in seconds = 86.4 * 0.036 = 3.1 seconds

7 0

2 years ago

Use the Hurricanes data and via Multiple regression select the three input variables: Min-pressure, Gender, Category in order to

S_A_V [24]

Answer:

Answer for the question:

Use the Hurricanes data and via Multiple regression select the three input variables: Min-pressure, Gender, Category in order to predict the All-Deaths. Pick one of the three variables that has the best P-value and re-do the regression using ONLY this one variable to predict the All-deaths. Answer the questions. (Numerical answers are rounded so choose the answer that matches the best).

is explained in the attachment.

Explanation:

Download pdf

6 0

3 years ago

A plane wall of length L, constant thermal conductivity k and no thermal energy generation undergoes one-dimensional, steady-sta

KIM [24]

Answer:

Temperature distribution is $T(x)=\dfrac{q}{k}(L-x)+T$

Heat flux=q

Heat rate=q A

Explanation:

We know that for no heat generation and at steady state

$\dfrac{\partial^2 T}{\partial x^2}=0$

$\dfrac{\partial T}{\partial x}=a$

$T(x)=ax+b$

a and are the constant.

Given that heat flux=q

We know that heat flux given as

$q=-K\dfrac{dT}{dx}$

From above we can say that

$a= -\dfrac{q}{K}$

Alos given that when x= L temperature is T(L)=T

$T= -\dfrac{q}{K}L+b$

$b=T+\dfrac{q}{K}L$

So temperature T(x)

$T(x)=-\dfrac{q}{K}x+T+\dfrac{q}{K}L$

$T(x)=\dfrac{q}{k}(L-x)+T$

So temperature distribution is $T(x)=\dfrac{q}{k}(L-x)+T$

Heat flux=q

Heat rate=q A (where A is the cross sectional area of wall)

6 0

2 years ago

A dairy in Fresno County discharges its wastewater to a circular treatment pond. The dairy wants to expand its operations, which

Strike441 [17]

Answer:

420.69 mg

Explanation:

i just did that last week

4 0

2 years ago

The clepsydra, or water clock, was a device that the ancient Egyptians, Greeks, Romans, and Chinese used to measure the passage

Nookie1986 [14]

Suppose a tank is made of glass and has the shape of a right-circular cylinder of radius 1 ft. Assume that h(0) = 2 ft corresponds to water filled to the top of the tank, a hole in the bottom is circular with radius in., g = 32 ft/s2, and c = 0.6. Use the differential equation in Problem 12 to find the height h(t) of the water.

Answer:

Height of the water = √(128)/147456 ft

Explanation:

Given

Radius, r = 1 ft

Height, h = 2 ft

Radius of hole = 1/32in

Acceleration of gravity, g = 32ft/s²

c = 0.6

Area of the hold = πr²

A = π(1/32)² ---- Convert to feet

A = π(1/32 * 1/12)²

A = π/147456 ft²

Area of water = πr²

A = π 1²

A = π

The differential equation is;

dh/dt = -A1/A2 √2gh where A1 = Area of the hole and A2 = Area of water

A1 = π/147456, A2 = π

dh/dt = (π/147456)/π √(2*32*2)

dh/dt = 1/147456 * √128

dh/dt = √128/147456 ft

Height of the water = √(128)/147456 ft

3 0

3 years ago