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sasho [114]
2 years ago
12

Which step in the engineering design process does not come before building a prototype?

Engineering
1 answer:
Mariana [72]2 years ago
6 0

Answer:

Step 1: Define. In this step, students formulate what they think about the problem. ...

Step 2: Ask. ...

Step 3: Imagine. ...

Step 4: Plan. ...

Step 5: Prototype. ...

Step 6: Test. ...

Step 7: Improve.

Explanation:

You might be interested in
Why is the lubrication system of an internal combustion engine equipped with an oil filter?
Ierofanga [76]

Answer:

to filter out any impurities such as metal shavings in the oil

6 0
3 years ago
With 64 KB of memory and 8 bits in each memory location, how wide should the address bus be to access all 64 KB of memory? (k =
marishachu [46]

Answer:

16-bit wide

Explanation:

In order to find the width of the address bus, we need first to know how many memory cells it is needed to address.

If the size memory is 64 KB, this means that the memory size, in bytes, is equal to the following quantity:

64 KB = 2⁶ * 2¹⁰ bytes = 2¹⁶ bytes.

In order to address this quantity of cell positions, the address bus must be able to address 2¹⁶ bytes, so it must have 16-bit wide.

3 0
3 years ago
REVIEW QUESTIONS
babunello [35]
Snap rings, and bearings can be used to keep a gear on a shaft, hope this helps!!
5 0
2 years ago
Ammonia enters the expansion valve of a refrigeration system at a pressure of 1.4 MPa and a temperature of 32degreeC and exits a
AveGali [126]

Answer:

the quality of the refrigerant exiting the expansion valve is 0.2337 = 23.37 %

Explanation:

given data

pressure p1 = 1.4 MPa = 14 bar

temperature t1 = 32°C

exit pressure = 0.08 MPa = 0.8 bar

to find out

the quality of the refrigerant exiting the expansion valve

solution

we know here refrigerant undergoes at throtting process so

h1 = h2

so by table A 14 at p1 = 14 bar

t1 ≤ Tsat

so we use equation here that is

h1 = hf(t1) = 332.17 kJ/kg

this value we get from table A13

so as h1 = h2

h1 = h(f2)  + x(2) * h(fg2)

so

exit quality  = \frac{h1 - h(f2)}{h(fg2)}

exit quality  = \frac{332.17- 9.04}{1382.73)}

so exit quality = 0.2337 = 23.37 %

the quality of the refrigerant exiting the expansion valve is 0.2337 = 23.37 %

5 0
3 years ago
What is the best way to submit your assignments?
Mrac [35]
A. Email your teacher right away. It would be the safest option.
4 0
3 years ago
Read 2 more answers
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