Answer:
Part a)

Part b)

Explanation:
Part a)
Proton is released from one plate and strike at other plate in time


now we will have



now we know that



Part b)
Speed of the proton when it strike the other plate can be calculated by kinematics equations



Explanation:
P.E=MGH
(1) P.E=5×10(G)×3
= 150 kg m^/s^ ( ^ =sqaure)
(2) P.E=5×10×6
= 300 kg m^/s^
Hope it helps, just remember the formula u can solve any question regarding gravition of earth (P.E=Mgh)
Change in speed = (speed at the end) minus (speed at the beginning)
= (0 - 20 m/s) = -20 m/s
Acceleration = (change in speed) / (time for the change)
= (-20 m/s) / (3.5 sec) = -5.71 m/s²
Notice that this story probably didn't happen on Earth, because
the acceleration due to gravity on Earth is 9.8 m/s².
Second law of physics. F = MA
200 = 25A
I believe you are capable of doing the rest
Answer:
go to the link quizzlet it will give you tha answer
Explanation: