Answer:
The answer is A, B, C, D
Explanation:
This is because gravity is the weakest force of the four fundamental forces, so it automatically cancels letter E
Answer:
A) the ammeter is x
B)
- voltage across R₁ (left resistor) = 0.75 V
- voltage across the right one = 0.3 V
C) 1.05 V
Explanation:
From the diagram attached below;
A) Assuming the homes were wired in series, and one of the homes face short circuit then all the houses would face power cut but it doesn't happen. So they must be connected in parallel.
Therefore; The ammeter is connected in series, Hence, the ammeter is x and the voltmeter must be z.
B)
Given that:
x = 0.15 A
z = 0.3 V
Resistor (R) on the left = 5 ohms
Then, voltage across R₁ (left resistor) = 5×(x)
= 5×0.15
= 0.75 V
voltage across the right one = z = 0.3 V
C)
The total voltage of battery = 0.75+0.3 = 1.05 V
Answer:
1.7 seconds
Explanation:
To clear the intersection, the total distance to be covered = 59.7 + 25 =84.7m
first we need to find the initial speed to just enter the intersection by using the third equation of motion
v^2 - u^2 = 2*a*s
45^2 - u^2 = 2 * -5.7 * 84.7
u^2 = 45^2 +965.58
u^2 = 2990.58
u = 54.7 m/s
Now for time we apply the first equation of motion
v-u =a * t
t = (v-u)/a = (45 - 54.7)/-5.7 = 1.7seconds
Answer:

Explanation:
Firstly, when you measure the voltage across the battery, you get the emf,
E = 13.0 V
In order to proceed we have to assume that the voltmeter offers no loading effect, which is a valid assumption since it has a very high resistance.
Secondly, the wires must be uniform. So the resistance per unit length is constant (say z). Now, even though the ammeter has very little resistance it cannot be ignored as it must be of comparable value/magnitude when compared to the wires. This is can seen in the two cases when currents were measured. Following Ohm's law and the resistance of a length of wire being proportional to it's length, we should have gotten half the current when measuring with the 40 m wire with respect to the 20 m wire (
). But this is not the case.
Let the resistance of the ammeter be r
Hence, using Ohm's law we get the following 2 equations:
.......(1)
......(2)
Substituting the value of r from (2) in (1), we have,

which simplifying gives us,
(which is our required solution)
putting the value of z in either (1) or (2) gives us, r = 0.5325 