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Yuri [45]
3 years ago
8

Which interactions are part of the greenhouse effect? Select three options.

Physics
2 answers:
Lisa [10]3 years ago
7 0

Answer:

a, d and E i id the quiz

Explanation:

Allisa [31]3 years ago
5 0

<u>Out of the given options, the following interactions are part of the greenhouse effect, </u>

  • Gases in the atmosphere absorb heat
  • Earth’s surface radiates energy back into the atmosphere
  • Gases in the atmosphere radiate heat back to the surface

Answers: Options A, D and E

<u>Explanation: </u>

The greenhouse effect, basically a warming effect caused by the greenhouse gases such as Carbon-Di-oxide, Methane, nitrous oxides, water vapour etc. These gases usually trap the heat that Earth Absorbs by the Sun.  

In the day time, the Earth absorbs the energy in the form of heat which is radiated by the Sun. In the evening, the process gets reversed and the Earth starts releasing that heat into the atmosphere.

Now, this heat gets absorbed by this gases before it leaves the Earth's atmosphere and gets trapped there only, resulting in the temperature raise of the Earth's environment.

So, the prime causes of the greenhouse effect remains as the heat radiation from the Sun, the absorption of that heat by the Earth surface and the further absorption of that heat produced by the greenhouse gases that present in the atmosphere.

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Heather and Matt take 34 minutes to walk eastward along a straight road to a store 2.0km away. What is their average velocity in
frez [133]

Their average velocity is 0.98 m/s east.

Explanation:

The average velocity of an object is defined as the ratio between the displacement and the time taken:

v=\frac{displacement}{time}

The displacement is a vector connecting the initial point to the final point of motion: so, being displacement a vector, velocity is a vector as well, having the same direction of displacement.

Here, Heather and Matt walk 2.0 km eastward, so their displacement is

d = 2.0 km = 2000 m (east)

While the time they took is

t=34 min \cdot 60 = 2040 s

Therefore, their average velocity is

v=\frac{2000}{2040}=0.98 m/s

And the direction is the same as the displacement (east).

Learn more about average velocity:

brainly.com/question/5248528

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Two go-carts, A and B, race each other around a 1.0 track. Go-cart A travels at a constant speed of 20.0 /. Go-cart B accelerate
maria [59]

Complete Question

Q. Two go-carts, A and B, race each other around a 1.0km track. Go-cart A travels at a constant speed of 20m/s. Go-cart B accelerates uniformly from rest at a rate of 0.333m/s^2. Which go-cart wins the race and by how much time?

Answer:

Go-cart A is faster

Explanation:

From the question we are told that

       The length of the track is l =  1.0 \ km  =  1000 \  m

       The speed of  A is  v__{A}} =  20 \ m/s

       The uniform acceleration of  B is  a__{B}} =  0.333 \ m/s^2

  Generally the time taken by go-cart  A is mathematically represented as

              t__{A}} = \frac{l}{v__{A}}}

=>          t__{A}} = \frac{1000}{20}

=>           t__{A}} =  50 \  s

  Generally from kinematic equation we can evaluate the time taken by go-cart B as

             l =  ut__{B}} + \frac{1}{2}  a__{B}} * t__{B}}^2

given that go-cart B starts from rest  u =  0 m/s

So

            1000 =  0 *t__{B}} + \frac{1}{2}  * 0.333  * t__{B}}^2

=>         1000 =  0 *t__{B}} + \frac{1}{2}  0.333  * t__{B}}^2            

=>         t__{B}} =  77.5 \  seconds  

 

Comparing  t__{A}} \  and  \ t__{B}}  we see that t__{A}} is smaller so go-cart A is  faster

   

       

3 0
3 years ago
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