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3 years ago

Which interactions are part of the greenhouse effect? Select three options.

Physics

2 answers:

Lisa [10]3 years ago

7 0

Answer:

a, d and E i id the quiz

Explanation:

Allisa [31]3 years ago

5 0

Out of the given options, the following interactions are part of the greenhouse effect,

Gases in the atmosphere absorb heat
Earth’s surface radiates energy back into the atmosphere
Gases in the atmosphere radiate heat back to the surface

Answers: Options A, D and E

Explanation:

The greenhouse effect, basically a warming effect caused by the greenhouse gases such as Carbon-Di-oxide, Methane, nitrous oxides, water vapour etc. These gases usually trap the heat that Earth Absorbs by the Sun.

In the day time, the Earth absorbs the energy in the form of heat which is radiated by the Sun. In the evening, the process gets reversed and the Earth starts releasing that heat into the atmosphere.

Now, this heat gets absorbed by this gases before it leaves the Earth's atmosphere and gets trapped there only, resulting in the temperature raise of the Earth's environment.

So, the prime causes of the greenhouse effect remains as the heat radiation from the Sun, the absorption of that heat by the Earth surface and the further absorption of that heat produced by the greenhouse gases that present in the atmosphere.

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an aircraft has a liftoff speed of 53 m/s. what is the minimum constant acceleration an airplane must have to reach that takeoff

xxMikexx [17]

Answer:

$a=3.34\ m/s^2$

Explanation:

Accelerated Motion

It refers to the motion of objects in which velocity is not constant over time. If the change of the velocity occurs at the same rate, then we say it's uniformly accelerated. Being $v_o$ = initial speed, $v_f$ = final speed, a= constant acceleration, x= distance traveled

Then, the scalar relation between them is

$v_f^2=v_o^2+2ax$

The aircraft needs to reach a liftoff speed of 53 m/s from rest (assumed) having only 420 meters to do so. We can compute the acceleration by solving for a

$\displaystyle a=\frac{v_f^2-v_0^2}{2x}$

$\displaystyle a=\frac{53^2-0^2}{2(420)}$

$\boxed{a=3.34\ m/s^2}$

6 0

2 years ago

PLS I NEED HELP ASAAP

Lerok [7]

Answer:

Option A

Explanation:

The Equation represents the displacement of the object which is represented by x

$x=t-t^2$

so, $x_0$ means when time is zero so we replace t with zero in the equation,

$x_0=(0)-(0)^2\\x_0=0$

now for v which is velocity we need to differentiate the function as the formula for velocity is rate of change of displacement over time so we derivate the equation once and get,

$v=1-2t\\$

now for $v_0$ we insert t = 0 and get

$v_0=1-2(0)\\v_0=1$

now for a which is acceleration the formula of acceleration is rate of change of velocity over time, so we differentiate the the equation of v(velocity) once or the equation of x(displacement) twice so now we get,

$a=-2$

so Option A is your answer.

Remember derivative of a constant is always zero because a constant value has no rate of change has its a constant hence the derivative is 0

5 0

2 years ago

A stuntwoman is going to attempt a jump across a canyon that is 77 m wide. The ramp on the far side of the canyon is 25 m lower

liq [111]

initial speed of the stuntman is given as

$v = 28 m/s$

angle of inclination is given as

$\theta = 15 degree$

now the components of the velocity is given as

$v_x = 28 cos15 = 27.04 m/s$

$v_y = 28 sin15 = 7.25 m/s$

here it is given that the ramp on the far side of the canyon is 25 m lower than the ramp from which she will leave.

So the displacement in vertical direction is given as

$\delta y = -25 m$

$\delta y = v_y * t + \frac{1}{2} at^2$

$-25 = 7.25 * t - \frac{1}{2}*9.8* t^2$

by solving above equation we have

$t = 3.12 s$

Now in the above interval of time the horizontal distance moved by it is given by

$d_x = v_x * t$

$d_x = 27.04 * 3.12 = 84.4 m$

since the canyon width is 77 m which is less than the horizontal distance covered by the stuntman so here we can say that stuntman will cross the canyon.

5 0

2 years ago

What are one of the ways the atmosphere recycle gases through interactions with the biosphere?

tino4ka555 [31]

Answer:

Though the process photosynthesis

Explanation:

One of the important ways by which the atmosphere recycle gases through interactions with the the biosphere is by photosynthesis.

The biosphere is the living component on the earth. The atmosphere is the gaseous envelope round the earth.

Photosynthesis is the process whereby green plants manufacture their food using carbon dioxide and water in the presence of sunlight to produce glucose and oxygen gas.
This way, atmospheric carbon dioxide is exchanged for oxygen gas.

This way, there is a sustained interaction between the atmosphere and biosphere.

3 0

2 years ago

Read 2 more answers

Two parallel conducting plates are separated by 10.0 cm, and one of them is taken to be at zero volts. (a) What is the magnitude

aivan3 [116]

Answer:

$E=6.8Kv/m$