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worty [1.4K]
4 years ago
10

Write an equation for a linear function whose graph has the given characteristics.

Mathematics
1 answer:
Sophie [7]4 years ago
7 0

Answer:

y-1=1/4(x-8)

x-4y-4=0

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Answers are needed urgently..ty​
SIZIF [17.4K]

Angle <QAB is =15° because the opposite angles of an isosceles triangle are equal.

The length of the straight line AB = 80cm

<h3>Calculation of angle of a triangle</h3>

The angle at a point = 360°

Angle AQB= 360 - 210° = 150

But the angle that makes up a triangle= 180°

180-150= 30°

But <QAB = <QBA because triangle AQB is an isosceles triangle.

30/2 = 15°

To calculate the length of the straight line the following is carried out using the sine laws.

a/ sina, = b sinb

a= 8cm, sin a { sin 15)

b= ? , sin B = 150

make b the subject formula;

8/sin15= b/sin 150

b= 8 × sin 150/sin 15

b= 80cm

Learn more about isosceles triangle here:

brainly.com/question/25812711

#SPJ1

7 0
2 years ago
How can you show that two objects are proportional with an equation
masha68 [24]
For an equation to be proportional, it must have no y intercept, and it must have a slope. So, 
<span>y=4x+4  This equation isn't proportional because it has a y-intercept (+4)
y=4x+2  </span>This equation isn't proportional because it has a y-intercept (+2)
y=4x      This equation is proportional because it has no y-intercept, and a                     slope.
6 0
3 years ago
translated 3 units right and 2 units up. Then it is rotated 270 counterclockwise about the origin resulting in quadrilateral PQR
Daniel [21]

Because the shape is not undergoing a dilation, the perimeter of the original image and the new image is the same. The only thing that is changing is the placement of the original figure.


I hope this helps! :)

4 0
3 years ago
What are 3 other names for the solutions to a quadratic function
pashok25 [27]

Zeros, roots, solutions, and solution sets are all 4 names

5 0
3 years ago
Consider the graph of the quadratic function y=-2(x + 2)2
krek1111 [17]

Answer:

1

Step-by-step explanation:

The quadratic function

y = -2(x + 2)²  - 1

has no real zeros because its vertex is located at (-2, -1) and it opens downward (the leading coefficient, -2, is negative)

A quadratic function has one real root if its vertex has the form (x, 0). If we add 1 to our equation, we get:

y = -2(x + 2)²  - 1 + 1 = -2(x + 2)²

which has point (-2, 0) as vertex

7 0
3 years ago
Read 2 more answers
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