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Answer:
4.70 moles of water have mass of 84.6g
Explanation:
Given data:
Number of moles of water = 4.70 mol
Mass in gram = ?
Solution:
Formula:
Mass = number of moles × molar mass
Molar mass of water is 18 g/mol
Mass = 4.70 mol × 18 g/mol
Mass = 84.6 g
Thus, 4.70 moles of water have mass of 84.6g.
Answer:
She will observe that the pressure on the tire is higher.
Explanation:
By the ideal gas law, the pressure and the temperature are directly proportional, so, if the temperature increases the pressure increases too:
PV = nRT (P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature).
The temperature is a measure of the average kinetic energy of the gas molecules, so when the temperature increases, the energy also increases, and the gas molecules will move more quickly, so they will collide more often between themselves and in the wall. Those collisions will be with more force because the velocity is higher.
So, the pressure will be higher, because it is the result of collisions of the gas molecules with the walls of the tire.
Answer:
Option (C) 1 × 10^−12
Explanation:
Step 1:
Data obtained from the question include:
[H+] = 1x10^−2
[OH−] =?
Step 2:
Determination of [OH−] . This is illustrated below:
[H+] x [OH−] = 1x10^-14
1x10^−2 x [OH−] = 1x10^-14
Divide both side by 1x10^−2
[OH−] = 1x10^-14 / 1x10^−2
[OH−] = 1x10^-12
Therefore, the [OH−] of the solution is 1x10^-12
Answer:
- The speed of the wave in the rope is 2 m/s
Explanation:
1. <u>Data</u>:
a) ν = 4 Hz
b) λ = 0.5 m
c) s = ?
2. <u>Physical principles and formula</u>:
The propagation of waves in a rope is a classical example of <em>transverse waves</em>: the pulse is inflected in the <em>vertical</em> direction and the wave travels in the <em>horizontal</em> direction, i.e. the pulse or vibration is perpendicular to the motion of the media particles.
The equation that relates <em>speed (s), wavelength (λ), frequency (ν) </em>is:
- wavelength = speed × period
- wavelenfth = speed / frequency
- meter = (meter/second) / second⁻¹
3. <u>Solution</u>:
