Answer
given,
change in enthalpy = 51 kJ/mole
change in activation energy = 109 kJ/mole
when a reaction is catalysed change in enthalpy between the product and the reactant does not change it remain constant.
where as activation energy of the product and the reactant decreases.
example:
ΔH = 51 kJ/mole
E_a= 83 kJ/mole
here activation energy decrease whereas change in enthalpy remains same.
Answer:
Hey mate I shall not tell you the answer I shall explain it to you after this if still you can't understand then say
Explanation:
Derive v = u + at by Graphical Method. Consider the velocity – time graph of a body shown in the below Figure
Derive s = ut + (1/2) at2 by Graphical Method. Velocity so time graph to derive the equations of motion.
Derive v2 = u2 + 2as by Graphical Method. Velocity–Time graph to derive the equations of motion.
I hope you understand now
enjoy your day
#Captainpower :)❤❤
Rotational speed would increase...
v = omega . r
which means it's directly proportional to radius...
Answer:

Explanation:
Ok, the average speed can be calculate with the next equation:
(1)
Basically the car cover the same distance "d" two times, but at different speeds, so:

and the total time would be the time t1 required to go from A to B plus the time t2 required to go back from B to A:

From basic physics we know:

so:


Using the previous information in equation (1)

Factoring:
(2)
Finally, replacing the data in (2)
