1. No
2.No
I hope this helps:)
Answer:
They experience the same pressure
Explanation:
To answer this question, we recall Pascal's, Law Pascal's law states that an increase in pressure at a point in a confined cylinder containing a fluid, there is also an equal increase at all other points in that cylinder.
According to Pascal's law the pressure if the pressure expereienced by the larger diameter piston increases, the pressure experienced by the smaller diameter piston also increases by the same amount
However considering that pressure = Force/area F1/A1 =F2/A2
thus where A1 = πD²÷4 and A2 = πD²÷ 16 we have
we have F1×4/πD² = F2×16/πD² or F1 = 4× F2
They experience the same pressure but the larger cylinder delivers four times the force transmitted from he outside to the smaller cylinder
Answer:
Explanation:
Let us look at all the answers definitions,
Sponsor would not work as it talks about a company offering you something in back for an advertisement.
Obtain would work as it means to acquire something.
Neglect would not work because it means to fail to care for something properly
Dismiss wouldn't work because it means to leave or allow to exit
Answer:
Have similar chemical properties
Explanation:
- The periodic table of elements is made up of groups or families and periods.
- Elements in the same group or chemical family share similar chemical properties.
- For example, elements in group II have similar chemical properties. They include Calcium and magnesium.
- A similar chemical property of group II elements is that they react with water to form metal hydroxide and hydrogen gas.
Answer:
The ability of the molecule to pack more tightly increases the melting point.
Explanation:
In hydrocarbons of same molecular formula, melting point is determined by:
- weak intermolecular forces
- Molecular symmetry
Higher the intermolecular forces and molecular symmetry, higher will be the melting point.
Intermolecular forces in hydrocarbons decreases with branching. Moreover, branching interfere the tight packing of the molecule in the crystal. Therefore, branched hydrocarbons tend to have lower melting point.
However, in highly branched hydrocarbons molecular symmetry increases which results in tight packing of the molecule in the crystal.
So, highly tight packed molecules tend to have high melting point.
As (CH3)2CHC(CH3)3 is highly branched and has high molecular symmetry, therefore, its melting point is highest among given.
So, among the given, option c is correct.
