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Anna007 [38]
3 years ago
10

Referring to the ground state orbital diagram of Fe and Fe3+, explain why iron is considered a ferromagnetic element.

Chemistry
1 answer:
krok68 [10]3 years ago
7 0

Iron having Z=26 with electronic configuration as [Ar]3d^64s^2 has 6 electrons in the 3d shell wherein 5 electrons are aligned parallely and 1 electron  as antiparallel.

Fe^3^+ having electronic configuration as [Ag]3d^5 has 5 electrons, all aligned in the same direction.

Iron, when kept in external magnetic field, the magnetic domains of the atom get aligned in one direction that means it becomes parallel and they remain parallel even after removing the magnetic field therefore, it is considered as ferromagnetic.

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You have 16.0 g of some compound and you perform an experiment to remove all of the oxygen, 11.2 g of iron is left. What is the
Makovka662 [10]

The empirical formula of this compound is Fe_2O_3

<h3>Empirical formula </h3>

To calculate the empirical formula of a compound, the value of moles of each element is needed.

As we have the information of the mass value, we will use the molar mass expression, which corresponds to:

MM_O = 16g/mol\\MM_Fe = 55.8g/mol

                                              MM = \frac{m}{mol}

  • O

                                                   16 = \frac{4.8}{x}

                                                   x = 0.3mol

  • Fe

                                                    55.8=\frac{11.2}{x}\\x = 0.2

As the value of the empirical formula must be an integer, simply multiply the two values ​​by a common factor:

                                                O = 0.3 \times 10 = 3\\Fe = 0.2 \times 10 = 2

                                                       Fe_2O_3

So, the empirical formula of this compound is Fe_2O_3.

Learn more about empirical formula: brainly.com/question/1247523

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