Answer:
This metal has a specific heat of 0.9845J/ g °C
Explanation:
Step 1: Given data
q = m*ΔT *Cp
⇒with m = mass of the substance
⇒with ΔT = change in temp = final temperature T2 - initial temperature T1
⇒with Cp = specific heat (Cpwater = 4.184J/g °C) (Cpmetam = TO BE DETERMINED)
Step 2: Calculate specific heat
For this situation : we get for q = m*ΔT *Cp
q(lost, metal) = q(gained, water)
- mass of metal(ΔT)(Cpmetal) = mass of water (ΔT) (Cpwater)
-5 * (15-100)(Cpmetal) = 20* (15-10) * (4.184J/g °C =
-5 * (-85)(Cpmetal) = 418.4
Cpmetal = 418.4 / (-5*-85) = 0.9845 J/g °C
This metal has a specific heat of 0.9845J/ g °C
Answer:
Gradual refinement
Explanation:
Gradual refinement is the process whereby the System Development Life Cycle goes through a series of development stages, each stage/phase refining the previous one.
To calculate the amount of the compound in the units of grams, we need to first obtain for the molar mass of the compound. We calculate as follows:
MgCl2 = <span>24.31 + (2 x 35.45) = 95.21 g/mol
</span><span>340 g MgCl2 ( 1 mol / 95.21 g ) = 3.57 mol MgCl2
Hope this answers the question. Have a nice day.</span>
The answer is rounded off to 0.0278 mol C6H12O6
