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Naya [18.7K]
3 years ago
8

Why does the evaporation of sweat cool down your skin?

Physics
2 answers:
Ne4ueva [31]3 years ago
6 0
So sweat<span> helps </span>cool<span> you </span>down<span> two ways. First, it makes </span>your skin<span> feel cooler when it's wet. And when it </span>evaporates<span> it removes some heat. But </span>sweat<span> will only </span>evaporato<span>in an environment where there isn't much water in the air.</span>
Sergeu [11.5K]3 years ago
4 0
It removes the heat on your skin
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A motorcycle stunt driver zooms off the end of a cliff at a speed of 41.9 meters per second. If he lands after 1.62 seconds, wha
tiny-mole [99]
Of the cliff?

Projectile motion
In the problem we are asked to find a height of certain cliff when a motorcycle stunt driver zoom out horizontally at the end the cliff at an initial velocity. So we will use one of the kinematics equation for projectile motion,

y
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v
o
y
t
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g
t

where
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o
y
is just equal to zero since we can assume that the driver zooms out horizontally,
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8 0
3 years ago
Help please help!!!!!!!!
Sidana [21]

1. Electron

2. Neutron

3. Nucleus

4. Atom

5. Molecule

6 0
2 years ago
The charges on the proton and electron are typically measured in: Select the correct answer below: volts amperes coulombs dalton
malfutka [58]

Answer: columbs

Explanation:

Electrical charge are measured in columbs, usually demoted as C. Hence, the charges on proton and electron will be measured in Coloumbs. It typically measures the amount of electricity conveyed per second by a current of 1 ampere. The other units Given such as ; Volt is used for measuring voltage, which is the pressure in an electrical source. AMPERE is used for measuring the current flowing through an electrical circuit.

Dalton is a unit of mass and is about 1.660 * 10^-27 kg

4 0
2 years ago
A tank contains gas at 13.0°C pressurized to 10.0 atm. The temperature of the gas is increased to 95.0°C, and half the gas is re
fomenos

Answer:

The pressure of the remaining gas in the tank is 6.4 atm.

Explanation:

Given that,

Temperature T = 13+273=286 K

Pressure = 10.0 atm

We need to calculate the pressure of the remaining gas

Using equation of ideal gas

PV=nRT

For a gas

P_{1}V_{1}=nRT_{1}

Where, P = pressure

V = volume

T = temperature

Put the value in the equation

10\times V=nR\times286....(I)

When the temperature of the gas is increased

Then,

P_{2}V_{2}=\dfrac{n}{2}RT_{2}....(II)

Divided equation (I) by equation (II)

\dfrac{P_{1}V}{P_{2}V}=\dfrac{nRT_{1}}{\dfrac{n}{2}RT_{2}}

\dfrac{10\times V}{P_{2}V}=\dfrac{nR\times286}{\dfrac{n}{2}R368}

P_{2}=\dfrac{10\times368}{2\times286}

P_{2}= 6.433\ atm

P_{2}=6.4\ atm

Hence, The pressure of the remaining gas in the tank is 6.4 atm.

4 0
3 years ago
5p - 14 = 8 p + 4 find p
Digiron [165]

Answer:

Explanation:

5p - 14 = 8p + 4

5p = 8p + 18 <-- Moving constants to one side; add the same number of +14 to both sides.

-3p = 18. <-- The same thing with the variable itself.

p = -6 <-- Divide both sides by negative 3.

6 0
3 years ago
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