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jok3333 [9.3K]
2 years ago
7

A mass is connected to a spring on a horizontal frictionless surface. The potential energy of the system is zero when the mass i

s centered on x = 0, its equilibrium position. If the potential energy is 3.0 J when x = 0.050 m, what is the potential energy when the mass is at x = 0.10 m?
Physics
1 answer:
xz_007 [3.2K]2 years ago
6 0

Answer:

U = 12 J.

Explanation:

The potential energy in a spring is given by the following formula

U = \frac{1}{2}kx^2

where k is the spring force constant and x is the displacement from the equilibrium.

If U = 3 J when x = 0.05 m, then k is

3 = \frac{1}{2}k(0.05)^2\\k = 2400~N/m

Using this constant, we can calculate the potential energy at x = 0.10 m:

U = \frac{1}{2}(2400)(0.1)^2 = 12 ~J

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A vacuum cleaner produces sound with a measured sound level of 75.0 dB. (a) What is the intensity of this sound in W/m2? W/m2 (b
jonny [76]

Answer:

Part a)

I = 3.16 \times 10^{-5} W/m^2

Part b)

P_o = 0.162 Pa

Explanation:

Part a)

Level of sound = 75 dB

now we know that

L = 10 Log\frac{I}{I_0}

here we know that

I_0 = 10^{-12} W/m^2

now we have

75 = 10 Log(\frac{I}{10^{-12}})

I = 3.16 \times 10^{-5} W/m^2

Part b)

Intensity of sound wave is given as

I = \frac{1}{2}\rho A^2\omega^2 c

here we know that

A = \frac{P_o}{Bk}

so we have

I = \frac{1}{2}\rho(\frac{P_o}{Bk})^2\omega^2 c

I = \frac{1}{2}\rho P_o^2 \frac{c^3}{B^2}

now we know

\rho = 1.2 kg/m^3

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now we have

3.16 \times 10^{-5} = \frac{1}{2}(1.2)P_o^2\frac{340^3}{(1.4\times 10^5)^2}

P_o = 0.162 Pa

5 0
3 years ago
Can an argon atom undergo vibrational motion?
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No. the answer to the question if can an argon atom undergo vibrational motion is no. it can not even spin either. the argon atom, or the argon is a chemical element that is the third most abundant gas in the earth's atmosphere. it is ore than twice as abundance as water vapor. Thank you for this question.
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On Mars, where air resistance is negligible, an astronaut drops a rock from a cliff and notes that the rock falls about d meters
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d = 0 + \frac{1}{2}g t^2

now if the same is dropped for 4t seconds of time

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3 years ago
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Bob is pushing a box across the floor at a constant speed of 1.7 m/s, applying a horizontal force whose magnitude is 70 N. Alice
OlgaM077 [116]

Answer:

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b) Alice used initially a greater force to accelerate the box up to needed speed and later reduced the external force to keep speed constant. The right choice is option b.

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