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3 years ago

7

A mass is connected to a spring on a horizontal frictionless surface. The potential energy of the system is zero when the mass i

s centered on x = 0, its equilibrium position. If the potential energy is 3.0 J when x = 0.050 m, what is the potential energy when the mass is at x = 0.10 m?

1 answer:

xz_007 [3.2K]3 years ago

6 0

Answer:

U = 12 J.

Explanation:

The potential energy in a spring is given by the following formula

$U = \frac{1}{2}kx^2$

where k is the spring force constant and x is the displacement from the equilibrium.

If U = 3 J when x = 0.05 m, then k is

$3 = \frac{1}{2}k(0.05)^2\\k = 2400~N/m$

Using this constant, we can calculate the potential energy at x = 0.10 m:

$U = \frac{1}{2}(2400)(0.1)^2 = 12 ~J$

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