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Evgesh-ka [11]
3 years ago
9

Four equal masses m are so small they can be treated as points, and they are equallyspaced along a long, stiff mass less wire. T

he distance between any two adjacent masses is ℓ . What is the rotational inertia Icm of this system about its center of mass (a point half way between the
Physics
1 answer:
gavmur [86]3 years ago
4 0

The moment of inertia of a point mass about an arbitrary point is given by:

I = mr²

I is the moment of inertia

m is the mass

r is the distance between the arbitrary point and the point mass

The center of mass of the system is located halfway between the 2 inner masses, therefore two masses lie ℓ/2 away from the center and the outer two masses lie 3ℓ/2 away from the center.

The total moment of inertia of the system is the sum of the moments of each mass, i.e.

I = ∑mr²

The moment of inertia of each of the two inner masses is

I = m(ℓ/2)² = mℓ²/4

The moment of inertia of each of the two outer masses is

I = m(3ℓ/2)² = 9mℓ²/4

The total moment of inertia of the system is

I = 2[mℓ²/4]+2[9mℓ²/4]

I = mℓ²/2+9mℓ²/2

I = 10mℓ²/2

I = 5mℓ²

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A rocket, weighing 4.36 x 10^4 N, has an engine that provides an upward force of 8.90 x 10^5 N. It reaches a maximum speed of 86
Pavel [41]

The net force on the rocket is  846400 N.

Answer:

Explanation:

It is known that weight is the influence of gravitational force acting on any mass of the object. So in the present case, the weighing force given is equal to the gravitational force acting on the rocket. Thus, the gravitational force will be acting towards downward direction. But an upward force is required by the rocket for thrusting purpose and that force is given as upward force. So the net force acting on the rocket is the vector addition of all the forces acting on the rocket. As in this case, only upward and downward force is acting on the rocket. The vector addition will be equal to subtraction of downward acting gravitational force from upward force or force provided by engine.

Net force = Engine force - Gravitational force = 890000-43600=846400 N

So the net force acting on the rocket is 846400 N.

8 0
3 years ago
Which example represents the impact of religion on culture in the United States? A. children receiving counseling at school B. f
dmitriy555 [2]

Answer:

D. Banks and offices closing on sunday.

Explanation:

Church is usually on sunday and people need a day off to do it because service is about 3 hours long. When banks and offices close on this day it shows how religion has affected our lives and our culture.

5 0
3 years ago
wo lacrosse players collide in midair. Jeremy has a mass of 120 kg and is moving at a speed of 3 m/s. Hans has a mass of 140 kg
Julli [10]

2.71 m/s fast Hans is moving after the collision.

<u>Explanation</u>:

Given that,

Mass of Jeremy is 120 kg (M_J)

Speed of Jeremy is 3 m/s (V_J)

Speed of Jeremy after collision is (V_{JA}) -2.5 m/s

Mass of Hans is 140 kg (M_H)

Speed of Hans is -2 m/s (V_H)

Speed of Hans after collision is (V_{HA})

Linear momentum is defined as “mass time’s speed of the vehicle”. Linear momentum before the collision of Jeremy and Hans is  

= =\mathrm{M}_{1} \times \mathrm{V}_{\mathrm{J}}+\mathrm{M}_{\mathrm{H}} \times \mathrm{V}_{\mathrm{H}}

Substitute the given values,

= 120 × 3 + 140 × (-2)

= 360 + (-280)

= 80 kg m/s

Linear momentum after the collision of Jeremy and Hans is  

= =\mathrm{M}_{\mathrm{J}} \times \mathrm{V}_{\mathrm{JA}}+\mathrm{M}_{\mathrm{H}} \times \mathrm{V}_{\mathrm{HA}}

= 120 × (-2.5) + 140 × V_{HA}

= -300 + 140 × V_{HA}

We know that conservation of liner momentum,

Linear momentum before the collision = Linear momentum after the collision

80 = -300 + 140 × V_{HA}

80 + 300 = 140 × V_{HA}

380 = 140 × V_{HA}

380/140= V_{HA}

V_{HA} = 2.71 m/s

2.71 m/s fast Hans is moving after the collision.

4 0
3 years ago
What happens to the resistance of a wire as it gets wider
Alchen [17]

Answer:

it snaps

Explanation:

the more force you put on it, the wired out it gets than it snaps. I think

5 0
3 years ago
The greater the amplitude of a wave a. The quieter the sound b. The higher the frequency of the sound c. The dimmer the light in
Stolb23 [73]

Answer:

The greater the amplitude the greater the energy.

(Think of a water wave - which carries greater energy a 1 ft wave or

a 10 ft wave)

8 0
3 years ago
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