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4 years ago

Why was it important to polish the copper strips and wire, the coin, and the nail in the electroplating experiment?

Chemistry

1 answer:

Ierofanga [76]4 years ago

7 0

Answer:

You need to have a clean surface for contact between the solution and the material.

Explanation:

The presence of impurity on the surface of the material, and lack of surface uniformity (smoothness) can reduce the effective contact between material and solution and can interfere with the electroplating process's success.

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What element is similar to Baruim

aivan3 [116]

Answer:

calcium ca

Explanation:

We can see here that the only element that is on the same group (column) as Ba (Barium) is Calcium (Ca).

3 0

3 years ago

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If an electrical current can run though a solution, it is said to contain what?

lesantik [10]

the answer i believe is electrolytes.

8 0

3 years ago

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An important reaction that takes place in a blast furnace during the production of iron is the formation of iron metal and CO2 f

ladessa [460]

Answer: Mass of $Fe_2O_3$ required to form 930 kg of iron is 1328 kg

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For iron:

Given mass of iron = 930 kg = 930000 g (1kg=1000g)

Molar mass of iron = 56 g/mol

Putting values in equation 1, we get:

$\text{Moles of iron}=\frac{930000g}{56g/mol}=16607mol$

The chemical equation for the production of iron follows:

$Fe_2O_3+3CO\rightarrow 2Fe+3CO_2$

By Stoichiometry of the reaction:

2 moles of iron are produced by = 1 mole of $Fe_2O_3$

So, 16607 moles of iron will be produced by = $\frac{1}{2}\times 16607=8303moles$ of $Fe_2O_3$

Now, calculating the mass of $Fe_2O_3$ from equation 1, we get:

Mass of $Fe_2O_3$ = $moles\times {\text {molar mass}}=8303\times 160=1328480g=1328kg$

Thus mass of $Fe_2O_3$ required to form 930 kg of iron is 1328 kg

6 0

3 years ago

Convert 3.09 x 10~3 m = nm

Dmitriy789 [7]

3090000000nm

since there's 1m = 1000000000nm

6 0

4 years ago

If you start with 89.3 g no(g) and 28.6 g h2(g), find the theoretical yield of ammonia.

Tatiana [17]

Balanced equation:
2 NO + 5 H2 ------> 2 NH3 + 2 H2O

2 moles NO react with 5 moles H2 to produce 2 moles NH3

Molar mass of NO = 30.00 g/mol 
86.3g NO = 86.3/30.00 = 2.877 moles of NO 

This will require: 2.877*5 / 2 = 7.192 moles of H2 

Molar mass of H2 = 2 g/mol 
25.6g H2 = 25.6/2 = 12.7 mol H2. 
You have excess H2 means the NO is limiting 

From the balanced equation: 
2 moles of NO will produce 2 moles of NH3 
2.877 moles of NO will produce 2.877 moles of NH3 

Molar mass NH3 = 17g/mol 
Mass NH3 produced = 2.877 * 17 = 48.91g

Hence the yield is = 48.91 g ~ 49 g

3 0

3 years ago

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