Answer:
a)
b)
c)
The estimate is low.
Explanation:
a) Using the energy conservation we have:
we have kinetic energy intially and gravitational potential energy at the maximum height.
b) We can use the equation of the gravitational force
(1)
We have that:
(2)
at the surface G will be:
Now the equation of an object at a distance x from the surface.
is:
Using that dv/dt is vdx/dt and integrating in both sides we have:
c) The difference is:
So the percent difference will be:
The estimate is low.
I hope it helps you!
Answer:
The minimum angular velocity of the platform what whould the block slides away is w= 2.26 rad/s.
Explanation:
m= 0.265 kg
r= 2.4 m
μ= 0.257
g= 9.8 m/s²
W= m * g
W= 2.597 N
Fr= μ * W
Fr= 0.66 N
∑F = m * ac
W+Fr = m * ac
(W+ Fr) / m = ac
ac= 12.29 m/s²
ac= w² * r
√(ac/r)= w
w= 2.26 rad/s
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For convenience write RC=D and solve the ODE dV/dt=-V/D which gives
<span>V=Ae^(-t/D) by separating the variables. </span>
<span>When t=0, V=10 and this gives A=10, </span>
<span>when t=2, V=1 giving 1=10e^(-2/D) and you can find D by taking lns of </span>
<span>each side. D=RC, so R=D/C </span>
<span>You should get 2.90X10^5 ohms</span>
Answer:
The correct answer is - 200000 J
Explanation:
We use the formula of kinetic energy:
The formula to calculate kinetic energy is,
Here,
Ec =1/2 x m x v^2
The mass of the roller coaster is, m = 1000 k
g
The speed of the roller coaster is, v = 20.0 m/s
Therefore,
Ec=1/2 x 1000kg x (20m/s)^2 = 200.000Joule
200,000J
Answer:
0,5 m/s²
Explanation:
v = d /t
v = 10 / 20
v = 0,5 m/s²
<h3>The velocity of the ball is 0,5 m/s²</h3>
