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scZoUnD [109]
3 years ago
13

Determine the kinetic energy of a 1000-kg roller coaster car that is moving with a speed of 20.0 m/s.

Physics
1 answer:
ankoles [38]3 years ago
7 0

Answer:

The correct answer is - 200000 J

Explanation:

We use the formula of kinetic energy:

The formula to calculate kinetic energy is,

Here,

Ec =1/2 x  m x v^2

The mass of the roller coaster is,  m  =  1000  k g

The speed of the roller coaster is, v = 20.0 m/s

 Therefore,

Ec=1/2 x 1000kg x (20m/s)^2 = 200.000Joule

200,000J

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A hanging wire made of an alloy of titanium with diameter 0.05 cm is initially 2.7 m long. When a 15 kg mass is hung from it, th
Svet_ta [14]

Answer:

Explanation:

Young's modulus of elasticity Y = stress / strain

stress = force / cross sectional area

= weight of 15 kg / π r²

= 15 x 9.8 / 3.14 x ( .025 x 10⁻² )²

stress = 74.9 x 10⁷ N / m²

strain = Δ L / L , Δ L is change in length and L is original length

Putting the values

strain = .0168 / 2.7 =.006222

Young's modulus of elasticity Y  = 74.9 x 10⁷ / .006222

= 120.88 x 10⁹ N / m² .

8 0
3 years ago
1. What is the average velocity of a car that moved 40 km East and 80 km West in 2 hours?
irina [24]

The average velocity is 20 km/h west

Explanation:

The velocity of an object is given by:

velocity = \frac{d}{t}

where

d is the displacement

t is the time elapsed

The displacement of an object is a vector connecting the initial position and the final position of motion.

In this problem, the car moved

40 km East

80 km West

Therefore, the displacement is given by (taking West as positive direction)

d=80 km - 40 km = 40 km West

The time elapsed is

t = 2 h

Therefore, the average velocity is

v=\frac{40 km}{2h}=20 km/h in the West direction.

Learn more about average velocity:

brainly.com/question/8893949

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7 0
3 years ago
There is a decrease in power. It can be concluded that there has also been a change in: A)current or voltage.
liraira [26]

A current or voltage

5 0
3 years ago
Please help with this one
olasank [31]

Answer:

OPTION A is the correct answer

6 0
3 years ago
The Bohr model of the hydrogen atom pictures the electron as a tiny particle moving in a circular orbit about a stationary proto
igor_vitrenko [27]

a) The angular velocity of the electron is 4.12\cdot 10^{16} rad/s

b) The number of revolutions per second is 6.54\cdot 10^{15} rev/s

c) The centripetal acceleration of the electron is 8.98\cdot 10^{22} m/s^2

Explanation:

a)

This is a problem of uniform circular motion: in fact, the electron orbits around the proton in a uniform circular motion.

The angular velocity of an object in uniform circular motion is given by

\omega = \frac{v}{r}

where

v is the linear speed

r is the radius of the trajectory

For the electron orbiting around the proton, we have

v=2.18 \cdot 10^6 m/s

r=5.29\cdot 10^{-11} m

Therefore, the angular velocity is

\omega=\frac{2.18\cdot 10^6}{5.29\cdot 10^{-11}}=4.12\cdot 10^{16} rad/s

b)

The period of revolution of the electron is given by

T=\frac{2\pi}{\omega}

where

\omega = 4.12\cdot 10^{16}rad/s is the angular velocity

Substituting,

T=\frac{2\pi}{4.12\cdot 10^{16}}=1.53\cdot 10^{-16}s

The period is the time the electron takes to make one complete orbit around the proton; therefore, the number of revolutions of the electrons in one second is:

f=\frac{1}{T}=\frac{1}{1.53\cdot 10^{-16}}=6.54\cdot 10^{15} rev/s

c)

The centripetal acceleration of an object in circular motion is

a=\frac{v^2}{r}

where

v is the linear speed

r is the radius of the circle

For the electron, we have

v=2.18 \cdot 10^6 m/s

r=5.29\cdot 10^{-11} m

Therefore, the centripetal acceleration is

a=\frac{(2.18\cdot 10^6)^2}{5.29\cdot 10^{-11}}=8.98\cdot 10^{22} m/s^2

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7 0
4 years ago
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