Answer:
Ver las respuestas a continuacion.
Explanation:
Para solucionar este tipo de problemas debemos de utilizar la siguiente ecuacion de la cinematica.
a)

Donde:
Vf = velocidad final [m/s]
Vo = velocidad inicial = 20 [m/s]
g = aceleración gravitacional = 9.81 [m/s²]
t = tiempo = 1 [s]
El signo negativo de la aceleración gravitacional significa que el objeto se mueve en dirección contraria a la aceleración gravitacional.
![v_{f}=20-9.81*(1)\\v_{f}=10.19[m/s]](https://tex.z-dn.net/?f=v_%7Bf%7D%3D20-9.81%2A%281%29%5C%5Cv_%7Bf%7D%3D10.19%5Bm%2Fs%5D)
b)
La altura máxima se logra cuando la velocidad final es cero, es decir no existe movimiento alguno para que siga subiendo el objeto. Debemos utilizar la siguiente ecuación de la cinemática.

Donde:
y = elevación [m]
![0 = 20^{2} -2*9.81*y\\19.62*y=400\\y=20.38 [m]](https://tex.z-dn.net/?f=0%20%3D%2020%5E%7B2%7D%20-2%2A9.81%2Ay%5C%5C19.62%2Ay%3D400%5C%5Cy%3D20.38%20%5Bm%5D)
c)
Podemos calcular el tiempo máximo que toma el objeto en subir.

![0 = 20 -9.81*t\\9.81*t=20\\t=2.04[s]](https://tex.z-dn.net/?f=0%20%3D%2020%20-9.81%2At%5C%5C9.81%2At%3D20%5C%5Ct%3D2.04%5Bs%5D)
Ahora del numeral b) sabemos la distancia maxima, de esta manera y utilizando la siguiente ecuacion podemos calcular el tiempo de caida, Debemos tener en cuenta que ahora la velocidad final es igual a la velocidad inicial = 0.

![20.38 = 0*t + 0.5*9.81*t^{2} \\20.38 = 4.905*t^{2}\\t=\sqrt{\frac{20.38}{4.905} } \\t=2.04[s]](https://tex.z-dn.net/?f=20.38%20%3D%200%2At%20%2B%200.5%2A9.81%2At%5E%7B2%7D%20%5C%5C20.38%20%3D%204.905%2At%5E%7B2%7D%5C%5Ct%3D%5Csqrt%7B%5Cfrac%7B20.38%7D%7B4.905%7D%20%7D%20%5C%5Ct%3D2.04%5Bs%5D)
Entonces el tiempo total es igual a:
t = 2.04 + 2.04
![t = 4.076 [s]](https://tex.z-dn.net/?f=t%20%3D%204.076%20%5Bs%5D)
Answer:
Explanation:
Mutual inductance is equal to magnetic flux induced in the secondary coli due to unit current in the primary coil .
magnetic field in a torroid B = μ₀ n I , n is number of turns per unit length and I is current .
B = 4π x 10⁻⁷ x (1000 / 2π x .16 )x 1 ( current = 1 A)
flux in the secondary coil
= B x area of face of coil x no of turns of secondary
= 4π x 10⁻⁷ x (1000 /2π x .16 ) .25 x 10⁻⁴ x 750
= 2 x 1000 x .25 x( 750 /.16) x 10⁻¹¹
2343.75 x 10⁻⁸
= 23.43 x 0⁻⁶ H.
.
Answer: a) io=233.28 A ( initial current); b) τ=R*C= 22.31 ms; c) 81.7 ms
Explanation: In order to explain this problem we have to use, the formule for the variation of the current in a RC circuit:
I(t)=io*Exp(-t/τ)
and also we consider that io=V/R=(1.5/6.43*10^3)
=233.28 A
then the time constant for the RC circuit is τ=R*C=6.43*10^3*3.47*10^-6
=22.31 ms
Finally the time to reduce the current to 2.57% of its initial value is obtained from:
I(t)=io*Exp(-t/τ) for I(t)/io=0.0257=Exp(-t/τ) then
ln(0.0257)*τ =-t
t=-ln(0.0257)*τ=81.68 ms
Answer:
1.) 15hrs per week = $97.50
2.) 20hrs per week = $130
Explanation:
Answer:
<em>About four million tons of </em><em><u>matter</u></em><em> are converted to energy in the Sun’s core every second</em>
Explanation:
<u>The Sun
</u>
It's estimated that The Sun fuses near 600 million tons
of hydrogen into helium every second. As a result, 4 million tons of matter are converted to energy every second according to Einstein's equation 